Tell whether the number given is solution of 32 greater than or equal to 7x plus 4?

2 answers:

7 0

Just substitute in the values in 32>7x+4
if x=-1 ---->32>7(-1)+4---->32>3 which is true.It is a solution
if x=5--->32>7(5)+4--->32>39 which is false.it is NOT a soultion
if x=0---->32>4---->which is true .It is a solution
if x=4---->32>7(4)+4---->which is true. it is a solution

sattari [20]3 years ago

7 0

Answer:

hi, the guy on top of me is right

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Anyone I need help with this problem plss

Nady [450]

Answer:

About 1.23 standard deviation above the mean

Step-by-step explanation:

From what we have here, we need to calculate the difference between the given value and the mean and divide by the standard deviation

That would be through calculating the z score as follows;

z-score = (x - mean)/SD

where x is the given value

z-score = (87-71)/13 = 1.23

Since the score is bigger than the mean, the correct choice here is that the score is about 1.23 standard deviation above the mean

3 0

3 years ago

The value of 37 − − √ − 24 − − √ 37−24 is between:

Effectus [21]

Answer:23 And 24

Step-by-step explanation:

((37 - (−√(−24))) - (−√(37))) - 24 =

19.0827625 + 4.89897949 i

19.0827625

+ 4.89897949

23.98174199

23.98174199 is between 23 and 24

3 0

3 years ago

The equation of a parabola is y=x^2-10x+27. Write the equation in vertex form

azamat

Answer:

$\large \boxed{y = (x - 5)^{2} + 2 }$

Step-by-step explanation:

y = x² - 10x + 27

y = ax² + bx + c

This is the general form of the equation for a parabola.

We must convert it to the vertex form

y = (x - h)² + k, where (h,k) are the coordinates of the vertex.

We can do this by completing the square.

$\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}$ The figure below shows that your parabola has its vertex at (5,2).