Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
1.7x 10 =17
Hope this helps
Answer:
D 5pi/2
Step-by-step explanation:
Found the circumference then quartered. Can I have brainiest I need one more to upgrade.
Step-by-step explanation:
We would do multiplication first, because of order of operations.
2x3=6
Now we add.
6+4=10
hope it helps! :3
Answer: 60 square units
Step-by-step explanation:
If you're supposed to find area it would be 5x7 + 5x5 = 35 + 25 = 60
