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Andru [333]
3 years ago
11

Solve the following inequality. 4x-1> -9

Mathematics
1 answer:
pychu [463]3 years ago
3 0
Solve inequalities the way you would solve an equation except for this rule-
If you multiply or divide a negative, the sign must be switched.

Do the inverse of everything like in an equation-
4x-1> -9
+1      +1 (Add 1)
4x>-8
/4    /4     (Divide 4)
You are not dividing a negative number from another number.  So keep the sign.
x>-2
Your answer is C.


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A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
The graph below is the solution for which sets of inequalities?
Reil [10]

Answer:

the first one

Step-by-step explanation:

i did the test and got it right

8 0
3 years ago
Solve the following​
Anastaziya [24]

Answer:

Q1

|a-b| = b-a when a<b

Q2

104159/33000

Step-by-step explanation:

Q1

If a<b then a-b will always be negative.  To get the absolute value, we can take -(a-b) = -a+b = b-a.

Q2

Let x = 3.12789789789...

We isolate the repeating decimal to start after the decimal, so we multiply by 100.

100x = 312.789789789...

We want to multiply by 10 for each digit that repeats (in this case 3), to get the repeating part to the left of the decimal.

100000x = 312789.789789

Subtracting the two...

x(100000-100) = 312789.789789 - 312.789789

99900x = 312477

x = 312477/99000 = 104159/33000

3 0
3 years ago
What is the z-score of a newborn who weighs 4,000 g?.
vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation  \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z tables, the p value we get is

P(Z \leq z) = \rm p \: value

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

  • X = weights of newborns for some considered system (in grams)
  • \mu = mean weight of newborns (in grams)
  • \sigma = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}

Thus, the z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

Learn more about z-scores here:

brainly.com/question/13299273

3 0
2 years ago
a company manufactures rectangular cardboard boxes. each box is 20 inches long and 15 inches wide. the heights of the boxes rang
Bogdan [553]

The range of possible values for the volume of the boxes would be 1200 - 1800 cubic inches

The dimensions of the rectangular cardboard boxes are given as

Case I

Length = 20 inches

breadth = 15 inches

Height = 4 inches

Volume of the rectangular cardboard box in case I = Length x breadth x breadth

= 20 x 15 x 4

= 1200 cubic inches

Similarly,

Case II

Length = 20 inches

breadth = 15 inches

Height = 6 inches

Volume of the rectangular cardboard box in case I = Length x breadth x breadth

= 20 x 15 x 6

= 1800 cubic inches

To learn more about volume, here

brainly.com/question/1578538

#SPJ4

4 0
2 years ago
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