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4 years ago

6

What is the particle's position at t =3.0s ? express your answer to three significant figures and include the appropriate units?

1 answer:

Tcecarenko [31]4 years ago

8 0

The only given information is the time in 3 seconds. We are asked to find the position, or the distance traveled. The working equation to be used here is:

x = v₀t + 1/2 at²
where
x is the distance
v₀ is the initial velocity
a is the acceleration

In order to solve this, let's assume the object is free falling. So v₀ = 0 and a = 9.81 m/s².

x = 0 + 1/2 (9.81)(3)²
x = 44.145 meters

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An atom that contains six protons six neutrons and six electrons has a mass of approximately

exis [7]

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Mass number = protons + neutrons

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3 years ago

Problem PageQuestion Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature

Marrrta [24]

Complete question

The complete question is shown on the first uploaded image

Answer:

The value is $K_c = 2.69 *10^{-5}$

Explanation:

From the question we are told that

The equation is

$Fe_20_3_{(s)}+3H_{(g)}\to2Fe_{(s)}+3H_2O_{(g)}$

Generally the equilibrium is mathematically represented as

$K_c = \frac{[H_2O]^2}{[H_2]^3}$

Here $[H_2O]$ is the concentration of water vapor which is mathematically represented as

$[H_2O ] = \frac{n_w}{V_s }$

Here $V_s$ is the volume of the solution given as 8.9 L

$n_w$ is the number of moles of water vapor which is mathematically represented as

$n_w = \frac{m_w}{Z_w}$

Here $m_w$ is the mass of water given as 2.00 g

and $Z_w$ is the molar mass of water with value 18 g/mol

So

$n_w = \frac{2}{18}$

=> $n_w = 0.11 \ mol$

So

$[H_2O ] = \frac{0.11}{8.9 }$

=> $[H_2O ] = 0.01236 \ M$

Also

$[H]$ is the concentration of hydrogen gas which is mathematically represented as

$[H ] = \frac{n_v}{V_s }$

Here $V_s$ is the volume of the solution given as 8.9 L

$n_v$ is the number of moles of hydrogen gas which is mathematically represented as

$n_v = \frac{m_v}{Z_v}$

Here $m_w$ is the mass of water given as 4.77 g

and $Z_v$ is the molar mass of water with value 2 g/mol

So

$n_w = \frac{4.77}{2}$

=> $n_w = 2.385 \ mol$

So

$[H_2O ] = \frac{2.385}{8.9 }$

=> $[H_2O ] = 0.265 \ M$

So

$K_c = \frac{( 0.01236 )^3}{ (0.265 )^2}$

=> $K_c = 2.69 *10^{-5}$

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3 years ago

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iogann1982 [59]

Answer:

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Explanation:

hope this helps :).

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