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2 years ago

_______ is the process in which light energy is transformed into food energy. A.life B.photosynthesis C.abiotic D.biotic

Chemistry

2 answers:

kolezko [41]2 years ago

4 0

Answer:

B) Photosynthesis is the process in which light energy is transformed into food energy.

Ymorist [56]2 years ago

4 0

Answer:

Photosynthesis

Explanation:

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Which of the following are interactions between particles in a liquid

NikAS [45]

Answer:

van der Waals forces

hydrogen bonds

Explanation:

both are interactions

3 0

2 years ago

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is 4.65 got copper is produced when 1.87 grams of

marta [7]

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield = ?

Actual yield of copper = 4.65 g

Mass of aluminium = 1.87 g

Mass of copper sulfate = excess

Solution:

Chemical equation:

2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

Al : Cu

2 : 3

0.07 : 3/2×0.07 =0.105 mol

Mass of Copper:(Theoretical yield)

Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

4 0

3 years ago

Which organelle acts as a temporary storage center, containing water,

JulsSmile [24]

The correct answer would be C, vacuole.

5 0

2 years ago

Read 2 more answers

Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

Answer:

For 1: The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2: The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

Explanation:

For 1:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

For 2:

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

6 0

2 years ago

What is the phase change in which a solid turns into a liquid

STatiana [176]

Answer:

melting

Explanation:

5 0

2 years ago