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sveta [45]
3 years ago
15

Vancouver Island is off the west coast of Canada, north of Washington State. The island is divided by mountains, the Vancouver I

sland Range. Describe what the climate must be like on the west and east sides of the mountain range.
a.The rain shadow effect would cause the east side to be more moist and green compared to the west side
b.The rain shadow effect would cause the east side to be more dry and barren compared to the west side.
c.Lake effect snow would drop on the east side but not on the west side.
Biology
2 answers:
lora16 [44]3 years ago
4 0

The rain shadow effect means the west coast of the Island is much wetter than the east coast. I did research on the mountain. Answer B. If you are on oddsyware I can confirm this is correct

Ganezh [65]3 years ago
3 0

Answer:

The rain shadow effect would cause the east side to be more dry and barren compared to the west side.So option B is correct.

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Which type of organism is described by the functions listed below?
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7 0
3 years ago
Classify the following organisms into their respective kingdoms (i) Yeast (ii) Penicillium (iii) Rhizobium (iv) Mushroom (v) Amo
lions [1.4K]

Answer:

(i) Yeast- Kingdom Fungi

(ii) Penicillium- Kingdom Fungi

(iii) Rhizobium- Kingdom Eubacteria

(iv) Mushroom- Kingdom Fungi

(v) Amoeba- Kingdom Protista

(vi) fish- Kingdom Animalia

Explanation:

Living organisms were classified into a large group called KINGDOM, which represent the largest and most generic grouping consisting of organisms that share a few similarities. The kingdoms that living organisms were classified into are as follows: Plantae, Animalia, Fungi, Protista, Eubacteria, Archaebacteria, etc.

Based on the question, the mentioned organisms are classified into the following kingdoms:

(I) Yeast: Yeast is a unicellular microbe classified under the Kingdom Fungi due to possession of chitin in its cell wall and other similar features with members of kingdom Fungi.

ii) Penicillium- Penicillium is a genus classified under the Kingdom Fungi.

(iii) Rhizobium- Rhizobium is a genus of prokaryotic organism (lack membrane-bound nucleus and organnelles) classified under the Kingdom Eubacteria.

(iv) Mushroom- Mushrooms are saprophytic (heterotrophic) species of organisms classified under the Kingdom Fungi.

(v) Amoeba- Amoeba is a genus of unicellular eukaryotes classified under the Kingdom Protista.

(vi) fish- Fishes are organisms classified under the Kingdom Animalia

3 0
3 years ago
An infant is born in the breech position, and assessment indicates the presence of erb palsy (erb-duchenne paralysis). which cli
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6 0
3 years ago
An additional gene, gene W, was also examined. A test cross was made between true-breeding EEWW flies and EEWW flies. The result
Debora [2.8K]

This question is incorrect but here is the correct question below;

An additional gene,gene W was also examined. a test cross was made between true breeding EEWW flies and eeww flies. The resulting F₁ generation was then crossed with eeww flies. 100 offspring in the F₂ generation were examined and it was discovered that the E and W genes were not linked.

Which is the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked?

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

b) Linked: 25% Eeww, 50% eeWw; not linked:parental genotypes EeWw and eeww.

c) Linked genotypes (EeWw and eeww) and recombinant genotype ( Eeww & eeWw) in the F₂ generation are nearly the same irrespective of their linkage.

d) Linked: mostly with parental genotypes, Eeww and eeWw; unlinked: 25% EeWw and eeww with 75% Eeww and eeWw.

Answer:

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

Explanation:

a test cross was made between true breeding EEWW flies and eeww flies

If EEWW self crossed, we have the following ( EW, EW, EW, EW)

Also, for eeww, we have ( ew, ew, ew, ew)

                   

                    EW                   EW                     EW                   EW

ew               EWew               EWew               EWew               EWew      

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

All offspring are  (EWew)

The question goes further by saying "The resulting F₁ generation was then crossed with eeww flies".

And we are asked to find the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked

∴

To determine  the offsprings of the linked genes we need to go by the definition and understand what linked genes are: Linked genes are genes that are physically close together on the same chromosomes. Effect of recombinantion on linked genes, results in gene swaps which occur in chromosomes that are homologous.

Having said that; If  EWew × eeww

we have;                 EW   &   ew    ×    ew  &    ew

           EW               ew

ew       EeWw          eeww

ew       EeWw          eeww

offspring that

are linked in   ⇒     EeWw    EeWw     &      eeww      eeww

F₂   will be

\frac{1}{2} = 50% of EeWw of the total 100 offspring in the F₂ cross

\frac{1}{2} = 50% of eeww of the total 100 offspring in the F₂ cross

∴ Linked genes =  50% EeWw and 50% eeww.

For unlinked genes; If  EWew × eeww

if rearrangement occurs in EWew  and EWew self crossed, we have ( EW,Ew,eW,ew) as the traits needed for the unlinked gene F₂ crossing.

Also ewew will be (ew, ew, ew, ew).

                       EW                    Ew                    eW                    ew

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

We have the following results for the unlinked genes

\frac{1}{4} = EeWw  25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = Eeww   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeWw   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeww    25% of the total 100 offspring in the F₂ cross

∴ not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

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JulsSmile [24]

Answer:

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3 0
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