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mote1985 [20]
3 years ago
7

Solve for X. Leave your answer in simplest radical form if necessary.

Mathematics
2 answers:
lord [1]3 years ago
8 0

:) Brainliest?

Answer:

x = sqrt 2, y = 2

Step-by-step explanation:

45-45-90 triangles have a ratio of 1 : 1 : sqrt2

tatyana61 [14]3 years ago
3 0

Answer:

x= √2

y= 2

Step-by-step explanation:

Side a = 2

Side b = 1.41421 = √2

Side c = 1.41421 = √2

Angle ∠A = 90° = 1.5708 rad = π/2

Angle ∠B = 45° = 0.7854 rad = π/4

Angle ∠C = 45° = 0.7854 rad = π/4

C=45°B=45°A=90°b=1.414a=2c=1.414

Area = 1

Perimeter p = 4.82843

Semiperimeter s = 2.41421

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Answer:

The width and height of the old 35-inch television are 28 inches and 21 inches, respectively.

Step-by-step explanation:

35-inch television is a television whose screen has an hypotenuse (l) of 35 inches and the aspect ratio of 4 : 3 means that 4 inches width per each 3 inches height. And by Pythagorean Theorem:

r_{l} =\sqrt{r_{w}^{2}+r_{h}^{2}}

Where:

r_{l} - Hypotenuse rate, dimensionless.

r_{w} - Width rate, dimensionless.

r_{h} - Height rate, dimensionless.

If r_{w} = 4\,in and r_{h} = 3\,in, the hypotenuse rate is:

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The width and height of the old television can be found with the help of trigonometric functions:

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w = l\cdot \cos \theta

w = l\times\left(\frac{r_{w}}{r_{l}} \right)

Height of 35-inch old television (h)

h = l\cdot \sin \theta

h = l\times\left(\frac{r_{h}}{r_{l}} \right)

Where \theta is the direction of the hypotenuse with respect to width, measured in sexagesimal degrees.

If r_{w} = 4, r_{h} = 3 and r_{l} = 5 and l = 35\,in, the width and height of the old 35-inch television:

w = (35\,in)\times \left(\frac{4}{5} \right)

w = 28\,in

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h = 21\,in

The width and height of the old 35-inch television are 28 inches and 21 inches, respectively.

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