Question

Graph the image of AABC after a translation 6 units right and 7 units down.

Answer 1

Answer:

Explanation:

From the given graph, we can see that the vertices of triangle ABC are;

$\begin{gathered} A(4,2) \\ B(4,4) \\ C(-4,1) \end{gathered}$

To translate 6 units right, we have to add 6 to the x-coordinates of each of the vertices of the triangle and to translate 7 units down, we have to subtract 7 from the y-coordinates of each of the vertices of the triangle as seen below;

$A^{\prime}(4+6,2-7)\rightarrow A^{\prime}(10,-5)$$B^{\prime}(4+6,4-7)\rightarrow B^{\prime}(10,-3)$$C^{\prime}(-4+6,1-7)\rightarrow C^{\prime}(2,-6)$

Below is the graph of the image of triangle ABC which is triangle A'B'C';