Answer:
2
Step-by-step explanation:
When the probability of an event is = 1 that means it's no longer a probability but a certainty, an assertion instead.
If today is Thursday, what is the probability tat tomorrow will be Friday?
It's equal to 1 since certainly tomorrow will be Friday
However In noticed that your problem is incomplete, hence we can't answer your last question
Kudos to the poster on the typeset math.
With cube roots we don't have to worry that things are positive.
![\sqrt[3]{16 x^4} - \sqrt[3]{128 x} = \sqrt[3]{2^4 x^4} - \sqrt[3]{2^7 x} = \sqrt[3]{2^3 x^3 2x} - \sqrt[3]{4^3 2 x} = 2x\sqrt[3]{2x} - 4\sqrt[3]{2 x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16%20x%5E4%7D%20-%20%5Csqrt%5B3%5D%7B128%20x%7D%20%3D%20%20%5Csqrt%5B3%5D%7B2%5E4%20x%5E4%7D%20-%20%5Csqrt%5B3%5D%7B2%5E7%20x%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E3%20x%5E3%202x%7D%20-%20%5Csqrt%5B3%5D%7B4%5E3%202%20x%7D%20%3D%202x%5Csqrt%5B3%5D%7B2x%7D%20-%204%5Csqrt%5B3%5D%7B2%20x%7D)
![= (2x-4)\sqrt[3]{2 x}](https://tex.z-dn.net/?f=%3D%20%282x-4%29%5Csqrt%5B3%5D%7B2%20x%7D%20%20%20)
We are given :
The cost of one adult ticket = a.
The cost of one child ticket = c.
<u>Roy buys</u>
6 adult tickets and 2 child tickets.
Total amount = $66.
Therefore, first equation for Roy total amount would be
<em>6a +2c = 66 --------------------(1)</em>
<u>Elisa buys</u>
5 adult tickets and 4 child tickets.
Total amount = $62.
Therefore, second equation for Elisa total amount would be
<em>5a +4c = 62 --------------------(1).</em>
Therefore,
<h3>Roy
<u>6</u>a + <u>2</u>c = <u>66</u></h3><h3>
Elisa <u>5</u>a + <u>4</u>c = <u>62.</u></h3>