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ValentinkaMS [17]
3 years ago
11

Traveling with a speed of 70 mph, a car covered a distance D miles in T hours. Write an equation that relates the distance D thi

s car travels in T hours. Use the equation to find the distance the car travels between 3:30 p.m. and 5:00 p.m.
Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
Just use the dirt method... Rate times time equals distance... Ok so it is traveling at a speed of 70 mph so that would be the rate (the speed). At first you don't know the distance but then it tells you in the end. So how many hours and minutes is it to get from 3:30 to 5:00? 2 hours and 30 minutes... So you just found the time. Then you times the rate/speed by the time and their you go! You get the distance!
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The bike owner counted 32 wheels and 18 seats.
ivann1987 [24]

Answer:

b = 14

u = 4

Step-by-step explanation:

I manually counted because I forgot how to solve this. HAHA

Hope this helps

4 0
3 years ago
Which number value would complete the table below?
Ratling [72]

Answer:

Your answer should be C or D.

Because it looks like it goes up 1.50 each time

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

7 0
3 years ago
What fraction of the pages did you read?
AleksAgata [21]
10 1/2 = 21/2

(21/2)  / 3
= 21/2 x 1/3
= 21/6
= 3 1/2

answer
3 1/2 pages
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=2%20%5Ctimes%202" id="TexFormula1" title="2 \times 2" alt="2 \times 2" align="absmiddle" class
EastWind [94]
4 (i literally had to think about this cause i thought it was too easy )
6 0
3 years ago
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