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yaroslaw [1]
2 years ago
15

Darian and Kyle went to the Cinema and purchased nachos and chocolates. Kyle purchased two nachos and one chocolate ,while Daria

n purchased one more nachos and two more chocolates and paid a total of $45. How much did Kyle pay if the cost of the nachos was twice the cost of the chocolate?
please show working :)
Mathematics
1 answer:
quester [9]2 years ago
4 0

The amount of money Kyle paid is $25.

<h3>Determine the price of nachos and chocolates </h3>

Two simultaneous equations can be derived from the question:

3n + 3c = $45 equation 1

n = 2c equation 2

Where:

  • n = price of nachos
  • c = price of chocolate

In order to determine the price of chocolates, please substitute for n in equation 1.

3(2c) + 3c = $45

6c + 3c = $45

9c = $45

c = $45/9 = $5

In order to determine the price of nachos, please substitute for c in equation 2:

n = 2($5)

n = $10

<h3>Amount Kyle paid </h3>

2($10) + $5

$20 + $5

= $25

To learn more about simultaneous equations, please check: brainly.com/question/25875552

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Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

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Let the cost of other groceries be G, and the cost of cans be X.

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If 5 cans were purchased,

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(2) -(1):

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5X +G -2x -G= 5.37

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X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

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G= 86.03 <em>(</em><em>simplify</em><em>)</em>

Total bill

= XC +G

= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

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