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4 years ago

What is the change in electrons for sulfur in the following reaction?

Chemistry

2 answers:

skelet666 [1.2K]4 years ago

5 0

Answer:

Lose 4 electrons

Explanation:

Answer for Educere/ Founder's Education

Murljashka [212]4 years ago

3 0

Answer:

A. Lose 4 electrons

Explanation:

The reaction equation is given as:

S + NO₃ → SO₂ + NO

The half equation of the reaction for S:

S → SO₂

For S to go into SO₂,

we move from an oxidation state of 0 to +4,

Finding the oxidation state of S in SO₂

a + (-2 x 2) = 0

a - 4 = 0

a = 4

This is a loss of 4 electrons

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3 years ago

When an alkaline earth metal, a, reacts with a halogen, x, the formula of the covalent compund formed should be a2x?

Ierofanga [76]

Alkaline earth metal are the elements present in II group in the periodic table and are known as 'Metals' and have a charge of +2.

Alkaline earth metals - Be , Mg Ca, Sr , Ba, Ra

Halogens are present in VII A group in the periodic table and are 'Non-metals' and have a charge of -1.

Halogens - F, Cl, Br, I, At

When Alkaline earth metal (metals) combine with Halogens (non-metals) the compound formed will be ionic compound and the formula of the compound will be based on the charges of the element.

When we write the formula of the ionic compound the charges of the elements get criss crossed.

For example - Mg (Alkaline earth metal) have a charge of +2 and Cl (Halogen) have a charge of -1 and when they combine to form the formula their charges get criss crossed and we will get $Mg_{1}Cl_{2}$ or $MgCl_{2}$

When an alkaline earth metal, A, reacts with a halogen, X, the formula of the Ionic compound formed should be $AX_{2}$

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4 years ago

How many grams of CO2 are produced from 6.7 L of O2 gas at STP?

Tasya [4]

<h3>Answer:</h3>

13 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

Using Dimensional Analysis

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 13.1637 \ g \ O_2$