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pogonyaev
3 years ago
12

What is the molecular formula of the compound CH2 with molar mass = 42.0 g/mol? A. C2H18 B. C2H4 C. CAHg O D. C3H6​

Chemistry
2 answers:
tatuchka [14]3 years ago
5 0

Answer:

D. C3H6

Explanation:

AP3X

Just took the quiz, its right

nika2105 [10]3 years ago
4 0

Answer:

i think c

Explanation:

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Each step in the following process has a yield of 70.0%. CH4+4Cl2⟶CCl4+4HCl CCl4+2HF⟶CCl2F2+2HCl The CCl4 formed in the first st
Nadusha1986 [10]

Answer:

n(HCl)=1.96 mol

Explanation:

CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

With ideal yields we will end up with 4 moles of HCl.

With 70% yields on every stage

n(HCl)=0.7*0.7*4=1.96 mol

8 0
3 years ago
Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

5 0
3 years ago
Calculate the pOH of a solution if the concentration of hydroxide ions (OH-) is 1.9 x 10-5M?
OLEGan [10]

Answer:

9.28

Explanation:

pOH refers to a measure of hydroxide ions concentration. pOH tells about the alkalinity of a solution. If pOH is less than 7 then aqueous solutions are alkaline, acidic if pOH is greater than 7 and neutral if pOH is equal to 7.

Concentration of the hydroxide ions = 1.9 x 10-5 M

pH = -log(1.9\times 10^{-5})=4.72

pOH = 14 - pH

=14 - 4.72 = 9.28

6 0
4 years ago
6. As you go down a family or group on the periodic table *
maks197457 [2]

Answer:

the atoms have more valence electrons

Explanation:

4 0
3 years ago
Read 2 more answers
Sucralfate (molecular weight: 2087 g/mol) is a major component of Carafate®, which is prescribed for the treatment of gastrointe
dybincka [34]

Answer:

Option b. 0.048 M

Explanation:

We have the molecular weight and the mass, from sulcralfate.

Let's convert the mass in g, to moles

1 g . 1 mol / 2087 g = 4.79×10⁻⁴ moles.

Molarity is mol /L

Let's convert the volume of solution in L

10 mL . 1L/1000 mL = 0.01 L

4.79×10⁻⁴ mol / 0.01 L = 0.048 mol/L

3 0
3 years ago
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