Question

How many grams of CO2 are produced from 6.7 L of O2 gas at STP?

Answer 1

Answer:

13 g CO₂

General Formulas and Concepts:

Chemistry

Atomic Structure

• Reading a Periodic Table
• Moles
• STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

• Using Dimensional Analysis

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Explanation:

Step 1: Define

Identify variables

[Given] 6.7 L O₂

[Solve] g O₂

Step 2: Identify Conversions

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

1. [DA] Set up:                                                                                                       $\displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})$
2. [DA] Divide/Multiply [Cancel out units]:                                                           $\displaystyle 13.1637 \ g \ O_2$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

13.1637 g CO₂ ≈ 13 g CO₂