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shtirl [24]
3 years ago
15

1. Patient is admitted with neck injury which has resulted in a loss of function in their thyroid.

Chemistry
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

A. (i think)

Explanation:

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Can anyone help me please this is due and i need help someone check over my answers
Yuliya22 [10]
4.) D
10.) C
12.) D
13.) D
14.) D
15.) D
5 0
4 years ago
Which of the following is NOT a type of joint?
Setler79 [48]
B. is ur answer I bieleve
8 0
3 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
When stomach acid helps to break down food into smaller particles this is
AVprozaik [17]

Answer:

chemical, is the answer your looking for

6 0
3 years ago
Part 1 of 1 - Question 3 of 20 5.0 Points 2H2 O2 - > 2H2O can be classified as what type of reaction?
mart [117]
2 H₂ + O₂ = 2 H₂O


Answer B    only synthesis.

hope this helps!
7 0
3 years ago
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