If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?
1 answer:
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Answer:
Step-by-step explanation:
The <u>width</u> of a square is its <u>side length</u>.
The <u>width</u> of a circle is its <u>diameter</u>.
Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.
<u>Formulas</u>
If the diameter is equal to the side length of the square, then:
Therefore:
So the ratio of the area of the circle to the original square is:
Given:
- side length (s) = 6 in
- radius (r) = 6 ÷ 2 = 3 in
Ratio of circle to square: