Answer:x=10/3
Step-by-step explanation:
Step-by-step explanation:
let p be the point which is at a distance of 4 units from the x-axis and at a distance of 5 units from the y axis
(i) When P lies in the first quadrant then the coordinates of P are (5,4).
(ii) When of P lies in the second quadrant then the coordinates of P are (-5,4).
(iii) When P lies in the third quadrant then the coordinates of P are (-5,-4).
(iv) When P lies in the fourth quadrant then the coordinates of P are (5,-4).
<h3>Hope it helps you!!</h3>
Answer:
D
Step-by-step explanation:
The domain of f(x) = -6x^2 - 10x + 13 is all real values.
For the range f(x) = -6x^2 - 10x + 13 written in vertex form is -6(x^2 + 5/3x - 13/6) = -6(x^2 + 5/3x + 25/36 - 13/6 - 25/36) = -6(x + 5/6)^2 - 6(-103/36) = -6(x + 5/6)^2 + 103/6
Range is all real values less than or equal to 103/6