The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
Answer:
Step-by-step explanation:
In the 3rd question, we are given the equation x ^ 3 + x ^ 2 + 2x + 24. One of the factors is x + 3. Now, we can use long division to find that the equation we have left is x^2 - 2x - 8. We can just factor this to get (x - 4) (x + 2). In the 3rd question, possible factors for the coefficient are 1, 2, -1, -2. Possible factors for the constant are 1, 7, -1, -7. Now, we can try out all of them. The possible factors are 1, 7, -1, -7, 2, 14, -2, -14.
Answer:
umm i'm not rly sure what's going on here...but here's how i'd do it
Step-by-step explanation:
3280.84x12=39370.08 which is about 3,9370 feet.
to double check let's do an algebraic expression
1/3280.84=x/12 cross multiply
x(1)=3280.84(12) simplify
x=39370.08
hope that helped.
Sin 45° = opposite side / hypotenuse
1/2 = 8/h
h = 16
2)6/12 = 1/2
1/2 = sin 45°
6√3/12 = √3/2
√3/2 = cos 30°
Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°
Angles = 30° , 45° , 105°
About 66 percent.
Because 24/36 are women, keep simplifying that divide by 6, 4/6, divide by 2, 2/3 = 0.66 = 66%.
