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alexdok [17]
3 years ago
13

I will give Brainliest to lucky person Answer this question its pretty had 5+5= 9 True or False?

Mathematics
2 answers:
AlekseyPX3 years ago
8 0

Answer:false

Step-by-step explanation:

Korvikt [17]3 years ago
3 0

Answer:

false

Step-by-step explanation:

5+5=10

5+4=9

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J(h - 9) + 2; use h=9, and j = 8
shepuryov [24]

It should be -6

8(8-9)+2

Step-by-step explanation:

3 0
3 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
Salaries of 49 college graduates who took a statistics course in college have a​ mean, x overbar​, of $ 65 comma 300. Assuming a
Molodets [167]

Answer: 60,540< \mu

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu

, where \sigma = Population standard deviation.

n= sample size

\overline{x} = Sample mean

z* = Critical z-value .

Given :  \sigma=\$17,000

n= 49

\overline{x}= \$65,300

Two-tailed critical value for 95% confidence interval = z^*=1.960

Then, the 95% confidence interval would be :-

65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu

=65,300-(1.96)\dfrac{17000}{7}< \mu

=65,300-4760< \mu

=60,540< \mu

Hence, the 95​% confidence interval for estimating the population mean (\mu) :

60,540< \mu

7 0
2 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST!!
Anestetic [448]
Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2

8 0
3 years ago
Out of a total of 300 animals in the zoo, 45 are birds. What percent of animals in the zoo are birds
Ulleksa [173]
The answer above isn't right- lol.

15% of the animals in the zoo are birds.

[45/300 is .15, or 15%.]
4 0
3 years ago
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