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DochEvi [55]
3 years ago
11

5 consecutive integers of 265

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0
N+n+1+n+2+n+3+n+4=265

5n+10=265

5n=255

n=51

So the integers are:

51,52,53,54, and 55
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What is the probability of obtaining five heads in a row when slipping a fair coin?
kipiarov [429]
We want the coin to land on heads on 5 out of 5 flips.

Each time, the coin has a 1/2 chance of landing on heads.

Since we want it to land on heads 5 times in a row, we multiply 1/2 five times to get the probability.

(1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1 / (2*2*2*2*2)

= 1 / 32

There is a 1/32 chance of landing heads five times in a row.

Have an awesome day! :)
4 0
4 years ago
Highschool level trigonometry!!! Need help knowing step by step how to find answer!
Goshia [24]

Answer:

\theta \approx 82.34^\circ

Step-by-step explanation:

Please refer to the attached diagram. (Apologies if the shading or resolution is a bit off.)

So, we want to find θ.

Since we formed a right triangle, we can use right triangle ratios.

We know the measure of the adjacent side to θ and the hypotenuse.

Therefore, we will use the cosine ratio:

\displaystyle \cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}

The adjacent side is 2 and the hypotenuse is 15. By substitution:

\displaystyle \cos(\theta)=\frac{2}{15}

Now, we will take the inverse cosine of both sides. So:

\displaystyle \theta=\cos^{-1}\Big(\frac{2}{15}\Big)

Use a calculator. Hence:

\theta \approx 82.34^\circ

The angle between the ground and the ladder is about 82.34°.

5 0
3 years ago
Tina has $60 to spend on craft supplies. The tax rate is 8.25%. What is the maximum amount she can spend on craft supplies befor
kolbaska11 [484]

Answer:

$55.43

Step-by-step explanation:

The maximum amount she can spend on craft supplies before taxes is such that when the tax rate is applied on (or multiplied with) the amount, the result is $60. As such, if the amount is x then x is such that

x + 8.25% * x = 60

x + 0,0825x = 60

1.0825x = 60

x = 55.427

This is the maximum amount that may be spent on craft supplies to ensure that the budget is not exceeded.

8 0
3 years ago
Read 2 more answers
Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe
Dimas [21]

Answer:

The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 6.4

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

So

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 72.3}{6.4}

X - 72.3 = 1.405*6.4

X = 81.29

The minumum numeric grade you have to earn to obtain an A is 81.29.

6 0
3 years ago
Two number cubes are rolled. Each number cube has sides numbered 1 through 6.
cricket20 [7]
There are a total of 6*6=36 outcomes (sums), of which 18 are odd, 18 are even, so the probability of getting an odd sum is 18/36
of the 36 outcomes, there are four fives and three tens, so the probability of getting a multiple of 5 is 7/36
but the four fives are also odd numbers, so we need to subtract 4/36
the result is: 18/36 +7/26 -4/36=21/36=7/12 =0.58333333

to see the total outcomes, Google image "two number cubes sum" or go to this website:
https://www.eduplace.com/math/mw/background/5/06b/te_5_06b_probability_devel.html

3 0
4 years ago
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