Answer:
because the water brings a cool breeze when the wind blows
Explanation:
Answer:
10.1g of H₂ are produced
Explanation:
To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:
<em>Moles Zn -Molar mass: 65.38g/mol-:</em>
307g * (1mol / 65.38g) = 4.696 moles
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
381g HCl * (1mol / 36.46g) = 10.45 moles
For a complete reaction of 10.45 moles of HCl are required:
10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn
As there are 4.696 moles of Zn, <em>Zn is the limiting reactant</em>
<em />
The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:
4.696 moles * (2.16g / mol) =
<h3>10.1g of H₂ are produced</h3>
Answer:
e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature
Answer:
Explained below
Explanation:
The human body has a normal core temperature of around 37°C to 38°C.
Now, if it is heated up to say 39° to 40°C, fatigue will start to set in and the brain begins to tell the muscles to slow down.
If it's now heated to higher temperatures above above 41°C, the body will begin to experience heat exhaustion and therefore will start to shut down.
Due to this process, the body can't even sweat at that stage because blood flow to the skin will stops thereby making the body feel cold and clammy. Thus, chemical processes/reaction in the body will begin to be affected and the cells inside the body will start to deteriorate and thus there is now a huge risk of having multiple organ failure.
BaCl2 reacts with KOH forming KCl which is a salt and Ba(OH)2 which is the precipitate.
The initial UNBALANCED equation expressing this reaction would be:
BaCl2 + KOH .............> KCl + Ba(OH)2
Now, we need to balance this equation:
we have two moles of Cl as reactants and one mole only as product. Therefore, we will multiply the KCl in the product by 2 and the KOH in the reactants by 2.
This will balance the equation as follows:
BaCl2 + 2KOH ......> 2KCl + Ba(OH)2
Noticing this equation, we will find that:
The precipitate was formed due to the combination of the Ba2+ ion with 2 OH- ions as follows:
Ba2+ + OH- ............> Ba(OH)2
