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4 years ago

N2+3H2-2NH3

Chemistry

1 answer:

NemiM [27]4 years ago

7 0

102 grams of ammonia is formed when 3 moles of nitrogen and 6.7 moles of hydrogen reacts.

Explanation:

The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.

We know that 1 mole of Nitrogen gives 2 moles of ammonia.

We have 3 moles of nitrogen here,

So, 6 moles of ammonia will be form

so from the formula

no of moles=mass/atomic mass

mass= no. of moles*atomic mass

= 6*17

= 102 grams of ammonia will be formed.

So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.

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Joe tries to neutralize 125mL of 2.0 M HCL with 175mL of 1.0M NaOH. will the neutralization reaction be completed? If not what i

Lemur [1.5K]

Answer:

1) The neutralization reaction will mot be completed.

2) pH = 0.6.

Explanation:

1) Will the neutralization reaction be completed?

For the neutralization reaction be completed; The no. of millimoles of the acid must be equal the no. of millimoles of the base.

The no. of millimoles of 125 mL of 2.0 M HCl = MV = (2.0 M)(125.0 mL) = 250.0 mmol.

The no. of millmoles of 175 mL of 1.0 M NaOH = MV = (1.0 M)(175.0 mL) = 175.0 mmol.

∴ HCl will be in excess.

∴ The neutralization reaction will mot be completed.

2) If not what is the pH of the final solution?

[H⁺] =[ (MV)HCl - (MV)NaOH]/V total = (250.0 mmol - 175.0 mmol) / (300.0 mL) = 0.25 M.

∵ pH = - log[H⁺]

∴ pH = - log(0.25) = 0.6.

4 0

3 years ago

Which best demonstrates an example of the common ion effect?

ella [17]

Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.

pure water.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.

Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.

$CuCl\rightleftharpoons Cu^++Cl^-$

$NaCl\rightarrow Na^++Cl^-$

When common ion such as $Cl^-$ from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.

6 0

3 years ago

Thirty grams of potassium chloride crystals are added to 400 mL of water. What is the molarity of this potassium chloride soluti

photoshop1234 [79]

Answer:

Molarity of potassium chloride is:

A. 1.0 M

Explanation:

Molarity is used to express the concentration of the solution.It is defined as the moles of solutes per liter volume of solution.It is denoted by M.

$molarity(M)=\frac{moles\ of\ solute}{volume\ of\ solution(ml)}\times 1000$

$M=\frac{n}{V(ml)}\times 1000$

Here'n' is the number of moles. It can be calculated using formula:

$n=\frac{given\ mass(w)}{molar\ mass}$

given mass=30 gm

Molar mass of KCl = mass of K+mass of Cl

= 39.098+34.45

= 74.55 g

$n=\frac{30}{74.55}$

n = 0.402 moles

$M=\frac{n}{V(ml)}\times 1000$

$M=\frac{0.402}{400}\times 1000$

$M=\0.001\times 1000$

M=1.00 M

So molarity of potassium chloride is 1.00 M

5 0

4 years ago

galvanic cell is powered by the following redox reaction: (g) (aq) (l)(aq) (s) (aq) Answer the following questions about this ce

kotykmax [81]

Answer:

Explanation:

1. the 1/2 reaction that occurs at the cathode

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

2 the 1/2 reaction that occurs at the anode

2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-

E0 = -0.59v

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

E0 = 1.39v

3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)

E0cell = 0.80v

5 0

3 years ago

How many molecules in each sample? 64.7 g N2 83 g CCl4 19 g C6H12O6

lilavasa [31]

Answer:

1.39x10²⁴ molecules N₂

.25x10²³ molecules CCl₄

6.38x10²² molecules C₆H₁₂O₆

Explanation:

First we convert the given masses into moles, using the compounds' respective molar mass:

64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂

83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄

19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆

Then we multiply each amount by Avogadro's number, to calculate the number of molecules:

2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules

0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules

0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules

3 0

3 years ago