3 years ago

Please help!! ASAP thanks

Mathematics

2 answers:

Brut [27]3 years ago

7 0

Answer:10

Step-by-step explanation:

dusya [7]3 years ago

4 0

Answer:9t

Step-by-step explanation:

Suc my butt again

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Which style do you like best out of the two choices<br><br> And yes that is not me obviously

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Answer:

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If the angles are represented in degrees, find both angles: \cos(3x+13)=\sin(2x+42) cos(3x+13)=sin(2x+42)

Sphinxa [80]

Answer:

cos34°

sin56°

Step-by-step explanation:

Sin(2x+42)= sin90-(3x+13)

Sin(2x+42) = sin(90-13-3x)

Sin(2x+42) = sin(77-3x)

2x + 42 = 77-3x

5x. = 35

X = 7

If x = 7

cos(3x+13) = cos((3*7)+13)

cos(3x+13) = cos(21+13)

cos(3x+13)= cos34

And

sin(2x+42) = sin((2*7)+42)

sin(2x+42)= sin (14+42)

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2 years ago

The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10

Nutka1998 [239]

If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

${a}^{2} + {b}^{2} = {c}^{2}$
Then you have to pose the formula in terms of one of the legs, so:

${a}^{2} = {c}^{2} - {b}^{2}$
$a = \sqrt{ {c}^{2} - {b}^{2}}$
So when you change the letter for numbers you have that:

$a = \sqrt{ {58}^{2} - {42}^{2} }$

a=40

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