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2 years ago

how many square feet of paper do you need to cover a cube with a side 10 in. long? Round your answer to two decimal places

Mathematics

2 answers:

Ket [755]2 years ago

8 0

The answer should be A.=4.17 sq ft

OverLord2011 [107]2 years ago

7 0

<span>Yes, this is the correct method. 10 in * (1 ft / 12 in) = 0.8333 ft, and the surface area of a cube is 6*s^2, where s is the edge length. Using s = 0.8333 in, I got a surface area of 4.17. If I used s = 0.833, I actually got 4.16, which is less accurate, so make sure you don't round too much when you do your calculations. XD

But I hope this helps!</span>

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Simplify the expression and show work.

nasty-shy [4]

Answer:

72/149

Step-by-step explanation:

Just to clarify, the curly braces mean the same thing as normal parenthesis.

(12 + 5^2) = (12 + 25) = 37

(-7-15)^2 = (-22)^2 = 484

6^3 = 216

(12 + 5^2) - (-7-15)^2 = 37 - 484 = 447

6^3 / ((12 + 5^2) - (-7 - 15)^2) = 216 / 447 = 72/149

4 0

2 years ago

5(1.07)^m=9.19 <br><br> Solve for m

tatiyna

The answer is 8.99 in decimal form

In exact for it In (1.838)/ In (1.07)

I hope one of them helps

7 0

2 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

If 1679 parts are made in 7 hours, what is the average rate at which these parts are being made per hour?

luda_lava [24]

1679/7
=239.85...
Rounds to 240
So average rate is 240

4 0

2 years ago

About 2% of the population has a particular genetic mutation. 400 people are randomly selected. Find the mean for the number of

sergeinik [125]

Answer:

200

Step-by-step explanation:

So it'll be 400 ÷ 2 = 200 , and a way to to check your way would be 200 x 2 = 400

5 0

2 years ago