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andreyandreev [35.5K]
3 years ago
8

Explain how the vertical line test can be used to determine if a graph is a function.

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

Example:

Anna71 [15]3 years ago
5 0

Answer:

Step-by-step explanation:

The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

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You can add 16 up until it reaches 120 If it goes over 120 then delete one of the 16 to only get 7 the answer is 7
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3 years ago
Simplify 30x^3y/6xy^5z^0
mr Goodwill [35]

Answer:

5x^2/y^4

Step-by-step explanation:

30x^3y/6xy^5

30x^2/6y^4

5x^2/1y^4

5 0
3 years ago
Determine if the function defines an inner product on R3, where u = (u1, u2, u3) and v = (v1, v2, v3). (Select all that apply.)
n200080 [17]

Answer:

u1v1 + u2v2 + u3v3

Step-by-step explanation:

Inner product is a method of multiplying vectors, with the outcome being a scalar. \

u = (u1, u2, u3) and v = (v1, v2, v3)

Inner product  = u.v = (u1, u2, u3). (v1, v2, v3)

= u1v1 + u2v2 + u3v3

7 0
3 years ago
Please help solve!!<br> -5|x|+4=14
eduard

Answer:

2

Step-by-step explanation:

|x| means absolute value

|x| means if x is positive or negative, its still positive

-5|x|+4=14

-5|x|=10

|x|= -2

answer is 2

3 0
2 years ago
Read 2 more answers
Compute the dimensions of gravitational constant G where F=Gm1m2/r^2​
VARVARA [1.3K]

Answer:

G=L^3/(T^2M)

Step-by-step explanation:

  1. G=(Fr^2)/Mm
  2. G=(ML^3)/(T^2M^2)
  3. G=L^3/(T^2M)
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3 years ago
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