If LaTeX: P\left(6,-2\right),\:Q\left(-2,\:8\right),\:R\left(-4,\:3\right),\:P ( 6 , − 2 ) , Q ( − 2 , 8 ) , R ( − 4 , 3 ) ,and
Burka [1]
Answer:
<h3>y = -1</h3>
Step-by-step explanation:
First let us get the slope of the line PQ and RS
For PQ;
Given P(6, -2) and Q(-2,8)
slope m = 8-(-2)/-2-6
slope of pQ = 10/-8
slope of PQ = -5/4
For RS
R ( − 4 , 3 ) and S(-9, y)
slope of RS = y-3/-9+4
slope of RS = y-3/-5
For PQ to be perpendicular to RS, the product of their slope must be -1
Hence -5/4 (y-3/-5) = -1
y-3/4 = -1
cross multiply
y-3 = -4
y = -4+3
y = -1
Hence the value of y for PQ to be perpendicular to RS is -1
Answer:
y = -1/3x - 11/3
Step-by-step explanation:
line a: y = -1/3x - 5
3 = -1/3(2) - b
3 = -2/3 - b
3 + 2/3 = b
3/1 + 2/3 = b
9/3 + 2/3 = b
11/3 = b
Answer:
y=-2/3x+2/3 i think... :)
Step-by-step explanation:
y=mx+b
-4=-2/3(-7)+b
-4=14/3+b
b=2/3
y=-2/3x+2/3
So,
Let Mercado's age be m and his daughter's age be d.
Our first equation: m = 37
Our second equation: m = 5 + 4d
Substitute 37 for m
37 = 5 + 4d
Subtract 5 from both sides
32 = 4d
Divide both sides by 4
8 = d
His daughter is 8 years old.