Answer:
Ted
Step-by-step explanation:
Answer:
Total Distance = 2 miles
Step-by-step explanation:
We know D = RT where
D is distance
R is rate (speed)
T is time
First Leg:
Rate = x mph
Time = 20/60 = 1/3 hour
Hence, D = RT, Distance = x * 1/3 = x/3 miles
Second Leg:
Rate = x - 1
Time = 30/60 = 1/2 hour
Distance = (x - 1) * 1/2 = (x-1)/2
Total distance is the sum of both the legs, hence,
Total distance = 
miles
Since both the distance are equal we can equate and solve:
Plugging this x = 3 into the total distance expression, we get:
Total distance, 2 miles
Answer:
Step-by-step explanation:
1) ?
I can't see what that one given angle is .. but it's that mystery angle subtracted from 180 give the angle BOA then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of 180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90 to find the angle BAX
2) ( as we would read normally)
You're making this really tough on me.. I can just barely read the equations
I think it's 1+6x and 7x-3 . b/c they are the same length sides you can set those equal
1+6x = 7x -3
4+6x = 7x
4 = x
that worked out well :
for the tangent.. it's Tan(Ф)= Opp/ Adj
but I don't know which side they want to solve for.. I think you may have left off some of the instructions???? :/
ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.
1+6(4) = 25
or
7(4)-3=25
tangent is 25
3)
x-2 = 2x-10
x+8 = 2x
8 = x
again they made it work out easy :)
Then plug 8 into either equation to find the length of the tangent lines
8-2=10
tangent is 10
4) = 2) ??? they are the same question maybe you meant to put something else?
Answer:
i believe its 27
Step-by-step explanation:25 times two= 50 27 times two= 54 +one more is 55. so it is 27
Answer: x = 1500/ n
Step-by-step explanation:
X- price per student
N- number of students
