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Darina [25.2K]
3 years ago
6

Our answer should be a complex number in the form a +bi where a and b are real numbers.

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

16 +88i

Step-by-step explanation:

8 x (11i + 2 ) =

Distribute

8*11i + 8*2

88i +16

Writing in the proper form

16 +88i

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sveta [45]

The answer is 13.7004166667

5 0
4 years ago
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What is the inverse of f(x)=3x+6 ?
scZoUnD [109]

Answer:

\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }

Step-by-step explanation:

hello,

we can write

fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}

hope this helps

3 0
3 years ago
4z−(−3z)=<br> combining like terms
uranmaximum [27]
For combining like terms: it is 7z
3 0
3 years ago
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For each value of y, determine whether it is a solution to -2y+75-5.<br> Is it a solution?
ser-zykov [4K]

Answer:

• No

• Yes

• Yes

• No

Step-by-step explanation:

To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.

-2y +7≤ -5

Subtract 7 on both sides:

-2y≤ -5 -7

-2y≤ -12

Divide by -2 on both sides:

y≥ 6

This means that the solution can be 6 or greater than 6.

-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.

_______

Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.

Here's an example to check if -10 is a solution.

-2y +7≤ -5

When y= -10,

-2y +7

= -2(-10) +7

= 20 +7

= 27

Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.

3 0
2 years ago
Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
Debora [2.8K]

So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
3 years ago
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