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Gnesinka [82]
3 years ago
11

Write the improper fraction as a mixed number or a whole number 13/4

Mathematics
1 answer:
Dominik [7]3 years ago
7 0
13/4 would be 3 1/4. this is because 4 can go into 13 3 times leaving 1/4 left over. hence making it a mixed number. as a whole number it would be 3.25 because 4 can go into 13 3 times and 1/4 is .25, hope this helps!:)
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If a polyhedron has 5 faces and 7 vertices, then it must have how many edges? Please show step-by-step work
Juli2301 [7.4K]

Answer:

10 edges

Step-by-step explanation:

we know that

The Euler's formula state that: In a polyhedron, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

V - E + F = 2

in this problem  we have

V=7\\E=?\\F=5

substitute the given values

7 - E + 5 = 2

solve for E

Combine like terms in the left side

12 - E = 2

subtract 12 both sides

- E = -10

Multiply by -1 both sides

E =10

8 0
3 years ago
A bag contains 48 skittles, identical except for color. There are twice as many yellow as red skittles and twice as many blue as
d1i1m1o1n [39]

Answer: x=17

Step-by-step explanation:

(5 + x)/(16 + x) = 2/3

Cross multiply to get:  

15+3x = 32 + 2x

3 0
4 years ago
The next number in the arithmetic sequence 15, 22, 29, is: <br><br>A) 34<br>B) 35<br>C) 36<br>D) 37​
harkovskaia [24]
ANSWER: C) 36
EXPLANATION: +7 is the sequence
4 0
2 years ago
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
2 years ago
Numbers that add to -0.5 and multiply to 1
Oliga [24]
Short Answer
There are two numbers
x1 = -0.25 + 0.9682i   <<<< answer 1
x2 = - 0.25 - 0.9582i   <<<< answer 2 
 
I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5    
y = - 0.5 - x       (1)
xy = 1               (2)

Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1               Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0          Order these by powers
-x^2 - 0.5x -1 = 0           Multiply though by - 1
x^2 + 0.5x + 1 = 0         Use the quadratic formula to solve this.

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

a = 1
b = 0.5
c = 1


\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add  as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out.  Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375

Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

The final result is 0.9375 and 0.0625 add up to 1
 
7 0
3 years ago
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