Write the improper fraction as a mixed number or a whole number 13/4

1 answer:

7 0

13/4 would be 3 1/4. this is because 4 can go into 13 3 times leaving 1/4 left over. hence making it a mixed number. as a whole number it would be 3.25 because 4 can go into 13 3 times and 1/4 is .25, hope this helps!:)

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A polygon has an area of 225 square meters. If the area is tripled, how does each side length change?

krok68 [10]

Let me tell you the process so that you get to the answer
Remember first that the area of a regular polygon with x sides has each of them a length which can be represented by y

A = 1/4 * xy^2 * Cot(180/x) 
The purpose is to solve for y, so we get 
y^2 = 4A/(xCot(180/x)) 
y = √(4A/(xCot(180/x)))

The thing we need to change is A in the previous formula and with that we can use the equaation to be a constant. This could be represented by Z
Z = √(4/(xCot(180/x)))
so
Y = Z√A
If we increase area by a factor s, y increases by a factor of √x.
So if you want to know the triple then you need to increase it by √3

3 0

2 years ago

NEED TO SHOW ALL WORK) For each of the equations given below, use the triangle method to solve for the

Lelechka [254]

Answer:

1) $a=\dfrac{F}{m}$

2) $m=\dfrac{p}{v}$

Step-by-step explanation:

1) The given equation is

$F=ma$

We need to solve this for a.

In the given triangle place single variable i.e., F, on the top and variables in the product in the bottom (order of m and a does not matter) as shown in the below figure.

Using the triangle and the operations (× and ÷), we get

$F=ma$

$a=\dfrac{F}{m}$

$m=\dfrac{F}{a}$

Therefore, the required answer is $a=\dfrac{F}{m}$ .

2) The given equation is

$p=mv$

We need to solve this for m.

In the given triangle place single variable i.e., p, on the top and variables in the product in the bottom (order of m and v does not matter) as shown in the below figure.

Using the triangle and the operations (× and ÷), we get

$p=mv$

$m=\dfrac{p}{v}$

$v=\dfrac{p}{m}$