Find the roots of the following equations. a) 4x+9=34 b) (x-4)(x+2)=0 c) 2x^2-6x+4=0

1 answer:

7 0

A. 4x + 9 = 34
 - 9 - 9
 4x = 25
 4 4
 x = 6.25

B. (x - 4)(x + 2) = 0
 x - 4 = 0 U x + 2 = 0
 + 4 + 4 - 2 - 2
 x = 4 x = -2

C. 2x² - 6x + 4 = 0
 2(x²) - 2(3x) + 2(2) = 0
2(x² - 3x + 2) = 0
 2 2
 x² - 3x + 2 = 0
 x = -(-3) +/- √((-3)² - 4(1)(2))
 2(1)
 x = 3 +/- √(9 - 8)
 2
 x = 3 +/- √(1)
 2
 x = 3 +/- 1
 2
 x = 3 + 1 U x = 3 - 1
 2 2
 x = 4 x = 2
 2 2
 x = 2 x = 1

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NEED HELP PLEASE!!! Given f(x)=9x+4 and g(x)= -5x+1, what is g(x)-f(x)?

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Answer:

g(x) - f(x) = -14x - 3

Step-by-step explanation:

We need to subtract the function f(x) = 9x + 4 from the function g(x) = -5 + 1. Rewriting these two functions in columns, we get

g(x)= -5x+1

- f(x) = -(9x+4) Note: Use parentheses as shown here.

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