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attashe74 [19]
3 years ago
11

Find the roots of the following equations. a) 4x+9=34 b) (x-4)(x+2)=0 c) 2x^2-6x+4=0

Mathematics
1 answer:
Masteriza [31]3 years ago
7 0
A. 4x + 9 = 34
    <u>      - 9   - 9</u>
          <u>4x</u> = <u>25</u>
           4      4
            x = 6.25

B. (x - 4)(x + 2) = 0
    x - 4 = 0    U    x + 2 = 0
    <u>  + 4 + 4</u>          <u>    - 2  - 2</u>
         x = 4                 x = -2

C.          2x² - 6x + 4 = 0
    2(x²) - 2(3x) + 2(2) = 0
            <u>2(x² - 3x + 2)</u> = <u>0</u>
                      2             2
                x² - 3x + 2 = 0
                x = <u>-(-3) +/- √((-3)² - 4(1)(2))</u>
                                      2(1)
                x = <u>3 +/- √(9 - 8)</u>
                               2
                x = <u>3 +/- √(1)
</u>                            2<u>
</u>                x =<u> 3 +/- 1
</u>                          2
                x = <u>3 + 1</u>    U    x = <u>3 - 1</u>
                         2                      2
                x = <u>4</u>                 x = <u>2</u>
                      2                       2
                x = 2                 x = 1
<u />
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PLEASE CAN ANYONE HELP!!!
DiKsa [7]

Answer:

x = 3

y = 4  

hey, I am not 100% sure of the certainty of my answers, I am using what I remember about that topic but I do not know if it is right or wrong, I hope I have helped you, I did what I could.

Step-by-step explanation:

-3x + 2y = 23

5x + 2y = -17

X solution:

(you cancel the y)

-3x = 23

5x = -17

(you combine all the values above with those below)

2x = 6

(solve the ecuation normaly)

x = 6/2 = 3

Y solution:

(you replace the x)

-3(3) + 2y = 23

5(3) + 2y = -17

-9 + 2y = 23

15 + 2y = -17

(you combine all the values above with those below)

6 + 4y = 6

(solve the ecuation normaly)

4y = 0

y = 4  

(I do not really know if the answer here is 0 or 4 since when passing the 4 to divide it would be 0/4 and I do not understand very well how that is solved)

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The sum of three consecutive number is 633 ,find the numbers
chubhunter [2.5K]

Answer:

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Step-by-step explanation:

If we denote the first number as x, then the second number can be written as x + 1 and the third number as x + 2.

The equation is:

x + (x + 1) + (x + 2) = 633

3x + 3 = 633

3x = 633 - 3

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So the three consecutive numbers we're looking for are: 210, 211, 212

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Answer:

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Nana76 [90]

Step-by-step explanation:

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the common ratio is r.

s2 = s1 × r

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