Question

A 2750-pound car is parked on a hill with a slant of 40° from the horizontal. How much force will keep it from rolling down the hill?

Answer 1

Answer:

1768.25 N

Step-by-step explanation:

We are given that

Weigh of car=w=2750 pounds

$\theta=40^{\circ}$

We have to find the force required to keep it from rolling down the hill.

Force required to keep it from rolling down the hill=$wsin\theta$

Substitute the values

Force required to keep it from rolling down the hill=$2750sin40$

Force required to keep it from rolling down the hill=$2750\times0.643$

Force required to keep it from rolling down the hill=1768.25 N