<span>By dividing the two numbers we get 104.3495... Rounding this number to two decimal places means that we must keep just 2 digits after the "." symbol, and round the last one of them. In our case, 104.3495... becomes 104.35.</span>
Answer:
30 game boxes
Step-by-step explanation:
We have to multiply the number of each shelf by the number of game boxes,
The store has 6 shelves and 5 game boxes on each shelf.
Therefore, the number of game boxes that there are is:
6 * 5 = 30 game boxes
Answer:
x = 80
Step-by-step explanation:
Combine − 3/5x and 7/20x to get -19/20x.
Then combine -19/20x and 1/4x and you get -7/10x.
Then you multiply both sides by -10/7 which is the reciprocal of -7/10.
Make -56(-10) one fraction.
Multiply -56 and -10 and you get 560.
Then divide 560 by 7 to get 80.
Answer:
No, the following expression is not a difference of squares. Binomial can not be factored as the difference of two perfect squares. 3 is not a square.
Step-by-step explanation:
Factor
15x^2 - 25
(15x)^2(-5)^5
Divide by 3 and factor
5(3x^2-5)
"Theory:
A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression."
I put a picture to help u understand.
Answer:
<em>The sum of 4 consecutive odd number is 80</em>
<em>Let X be the first of these numbers</em>
<em>Then the next odd number is X+2</em>
<em>The third is X+4The fourth is X+6</em>
<em>All of these add up to 80</em>
<em>(X) + (X+2) + (X+4) + (X+6) = 80</em>
<em>Using the commutative and associative laws, let's transform this equation into</em>
<em>(X + X + X + X) + (2 + 4 + 6) = 804X + 12 = 80</em>
<em>Subtract 12 from both sides of the equation gives4X = 68</em>
<em>Divide both sides by 4 gives</em>
<em>X = 17</em>
<em>Going back to the original question:What are the 4 consecutive odd numbers: 17, 19, 21, 23Checking our answer:17 + 19 + 21 + 23 = 80 Correct!</em>
