F(x)=3x²-6x+13
a=3, b=-6, c=13
the x coordinate of the vertex is x=-b/(2a), so x=-(-6)/(2*3)=1
when x=1, y=3(1)²-6(1)+13=10
the vertex is at (1,10)
answers are in bold.
Hello,
Let's assume n the first integer
n+1 the greater
n+(n+1)=2n+1 is odd but 42 (universel answer in Robots IE) is even!!!!
Not answer!
Answer:
12% of 315 is 37.8 :) Tag me if I'm wrong
To live on campus is when you have almost like a hotel room but you may share it and it is linked to you school
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
