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Sidana [21]
3 years ago
12

Does knowing the distance between two objects give you enough information to locate the objects? explain

Physics
1 answer:
vodka [1.7K]3 years ago
3 0

By knowing the distance between two objects we can not get  enough ideas about the location of these respective objects. It can be easily understood from a simple example.

Let us consider two bodies A and B which are in a two dimensional plane. .Let the co-ordinates of body A  is [2,2].

Let us consider two possible co-ordinate pairs [1,0] and [0,1]

Let the body B is at [1,0].

Hence the distance between A and B  is AB=\sqrt{[2-1]^2+[2-0]^2}

                                                                    AB=\sqrt{1+4}

                                                                     AB=\sqrt{5}

Let the body B is shifted to [0,1] now.

Now  the distance between A and  B will be AB=\sqrt{[2-0]^2+[2-1]^2}

                                                                          AB=\sqrt{4+1}

                                                                           AB=\sqrt{5}

Here we observe that distance in each case is same .But in first case the body  B was on +X- axis while in second case the body B was on +Y- axis.

Hence distance between points may be same in different planes, but only the distance can not get enough ideas about the location of the objects.It is  the points in specific reference frames gives the ideas about the location of the objects. As position is relative ,hence for complete location of a object,the observer also plays a vital role here.


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Sindrei [870]

Answer:

Partial Pressure of F₂ = 1.30 atm

Partial pressure of Cl₂ = 0.70 atm

Explanation:

Partial pressure for gases are given by Daltons law.

Total pressure of a gas mixture = sum of the partial pressures of individual gases

Pt = P(f₂) + P(cl₂)

Partial pressure = mole fraction × total pressure

Let the mass of each gas present be m

Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol

Number of moles of Cl₂ = m/71 (molar mass of Cl₂)

Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65

Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35

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7 0
3 years ago
Master of physics needed
Delicious77 [7]
Hey JayDilla, I get 1/3.  Here's how:
Kinetic energy due to linear motion is:
E_{linear}= \frac{1}{2}mv^2
where
v=r \omega
giving
E_{linear}= \frac{1}{2}mr^2 \omega ^2

The rotational part requires the moment of inertia of a solid cylinder
I_{cyl} =  \frac{1}{2}mr^2
Then the rotational kinetic energy is
E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2
Adding the two types of energy and factoring out common terms gives
\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part.  Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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777dan777 [17]

Answer:

The minimum distance in which the car will stop is

x=167.38m

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39.7\frac{mi}{h}*\frac{1km}{0.621371mi}*\frac{1000m}{1km}*\frac{1h}{3600s}=17.747\frac{m}{s}

∑F=m*a

∑F=u*m*g

The force of friction is the same value but in different direction of the force moving the car so it can stop so

F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }

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Answer:

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mass of the string, m = 0.002 kg

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wavelength, λ = 1.5 m

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