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vovangra [49]
3 years ago
6

Physics I need help :(​

Physics
1 answer:
kvv77 [185]3 years ago
7 0
The correct answer is C july-september plz mark as brainliest!
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A book that has a mass of 0.5 grams is pushed across a table with a force of 20 newtons what is the acceleration of the book? A.
Valentin [98]

Answer:

Explanation:

To solve this equation ,we need to apply Newton's second law. Which defines

Force = Mass* Acceleration

Mass  = 0.5 g = 0.5*10^-3 Kg

Force  = 20 N

Acceleration = Force / Mass

Acceleration  = 20 N /0.5*10^-3 Kg

Acceleration  = 40000 m/s^2

I believe you meant a mass of 0.5 Kg

In that case, the acceleration would be

Acceleration  = 40 m/s^2

Option C

8 0
3 years ago
Read 2 more answers
Suppose a baseball pitcher throws the ball to his catcher.
amm1812

a) Same

b) Same

c) Same

d) Throw the ball takes longer

e) F is larger when the ball is catched

Explanation:

a)

The change in speed of an object is given by:

\Delta v = |v-u|

where

u is the initial velocity of the object

v is the final velocity of the object

The change in speed is basically the magnitude of the change in velocity (because velocity is a vector, while speed is a scalar, so it has no direction).

In this problem:

- In situation 1 (pitcher throwing the ball), the initial velocity is

u = 0 (because the ball starts from rest)

while the final velocity is v, so the change in speed is

\Delta v=|v-0|=|v|

- In situation 2 (catcher receiving the ball), the initial velocity is now

u = v

while the final velocity is now zero (ball coming to rest), so the change in speed is

\Delta v =|0-v|=|-v|

Which means that the two situations have same change in speed.

b)

The change in momentum of an object is given by

\Delta p = m \Delta v

where

m is the mass of the object

\Delta v is the change in velocity

If we want to compare only the magnitude of the change in momentum of the object, then it is given by

|\Delta p|=m|\Delta v|

- In situation 1 (pitcher throwing the ball), the change in momentum is

\Delta p = m|\Delta v|=m|v|=mv

- In situation 2 (catcher receiving the ball), the change in momentum is

\Delta p = m\Delta v = m|-v|=mv

So, the magnitude of the change in momentum is the same (but the direction is opposite)

c)

The impulse exerted on an object is equal to the change in momentum of the object:

I=\Delta p

where

I is the impulse

\Delta p is the change in momentum

As we saw in part b), the change in momentum of the ball in the two situations is the same, therefore the impulse exerted on the ball will also be the same, in magnitude.

However, the direction will be opposite, as the change in momentum has opposite direction in the two situations.

d)

To compare the time of impact in the two situations, we have to look closer into them.

- When the ball is thrown, the hand "moves together" with the ball, from back to ahead in order to give it the necessary push. We can verify therefore that the time is longer in this case.

- When the ball is cacthed, the hand remains more or less "at rest", it  doesn't move much, so the collision lasts much less than the previous situation.

Therefore, we can say that the time of impact is longer when the ball is thrown, compared to when it is catched.

e)

The impulse exerted on an object can also be rewritten as the product between the force applied on the object and the time of impact:

I=F\Delta t

where

I is the impulse

F is the force applied

\Delta t is the time of impact

This can be rewritten as

F=\frac{I}{\Delta t}

In this problem, in the two situations,

- I (the impulse) is the same in both situations

- \Delta t when the ball is thrown is larger than when it is catched

Therefore, since F is inversely proportional to \Delta t, this means that the force is larger when the ball is catched.

6 0
4 years ago
A cell has an internal resistance of 0.02ohms and e.m.f of 2.0v calculate it's terminal p.d if it's delivers (a)5A ( b)50A​
Aleksandr-060686 [28]

Answer:

(a) The terminal voltage of the cell is <u>1.9 V.</u>

(b) The terminal voltage of the cell is <u>1.0 V.</u>

Explanation:

Given:

(a)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 5 A

Now, the potential difference across the terminals of the cell is given as:

V=E-Ir

Plug in the given values and solve for 'V'. This gives,

V=2.0-(5\times 0.02)\\\\V=2.0-0.1=1.9\ V

Therefore, the terminal voltage of the cell is 1.9 V.

(b)

E.M.F of the cell (E) = 2.0 V

Internal resistance of the cell (r) = 0.02 ohms

Current passing through the cell (I) = 50 A

Now, the potential difference across the terminals of the cell is given as:

V=E-Ir

Plug in the given values and solve for 'V'. This gives,

V=2.0-(50\times 0.02)\\\\V=2.0-1.0=1.0\ V

Therefore, the terminal voltage of the cell is 1.0 V.

4 0
3 years ago
When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?
N76 [4]

Answer:

1 / f = 1 / o + 1 / i

1 / image distance + 1 / object distance = 1  focal length

If the object distance is large the image will be at about the focal length

The value of 1 / f is fixed for any one particular lense

As the object distance decreases the image must increase

The above equation can also be written as

o i / (i + o) = f    or i / (i / o + 1)  = f

If for instance o was very large the image would be at the focal length

6 0
3 years ago
The theory of _____ suggests that the crust of the earth is divided into pieces and moves about on the upper mantle.
nirvana33 [79]
Plate tectonics and the earth is separated into many pieces which move around and create earthquakes and volcanoes
6 0
4 years ago
Read 2 more answers
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