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USPshnik [31]
3 years ago
6

A 60.0-kg person rides in elevator while standing on a scale. The elevator is traveling downward butslowing down at a rate of 2.

00 m/s2. The reading on the scale is closest toA) 589 N.B) 708 N.C) 469 N.D) 120 N.

Physics
2 answers:
Katarina [22]3 years ago
7 0

The reading on the scale is closest to B) 708 N

\texttt{ }

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of the person = m = 60.0 kg

acceleration of the elevator = a = 2.00 m/s²

<u>Asked:</u>

reading of the scale = N = ?

<u>Solution:</u>

We will use Newton's second law of motion to solve this problem :

\Sigma F = ma

N - w = ma

N - mg = m a

N = mg + ma

N = m ( g + a )

N = 60.0 ( 9.8 + 2.00 )

N = 60.0 ( 11.8 )

N = 708 \texttt{ N}

\texttt{ }

<h3>Conclusion :</h3>

The reading on the scale is closest to 708 N

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

irga5000 [103]3 years ago
6 0

Answer:

C) 469 N

Explanation:

The reading on the scale corresponds to the normal reaction exerted by the scale on the person, R.

There are two forces acting on the person:

- Its weight (acting downward), equal to mg, where m = 60 kg is the mass of the person and g = 9.81 m/s^2 is the acceleration due to gravity

- The normal reaction of the scale, R, acting upward

According to Newton's second law, the resultant of these two forces must be equal to the product between mass and acceleration:

mg-R=ma

where we know that a=2.00 m/s^2 since the elevator is traveling downward at 2.00 m/s^2. Solving the equation for R, we find

R=m(g-a)=(60 kg)(9.81 m/s^2-2.0 m/s^2)=469 N

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