The acceleration is 1.67 m/s²
<u>Explanation:</u>
Given:
Speed, s = 60km/hr
s = 
m/s
s = 16.67 m/s
Time, t = 10 seconds
Acceleration, a = ?
We know:
On substituting the value, we get:
Therefore, the acceleration is 1.67 m/s²
Answer:
Doubling the wavelength of the diffracting doubles the angle of diffraction. So, the width of the central bright spot pattern formed on the screen will also be doubled.
Explanation:
For a single slit diffraction, the path length difference is related to the wavelength of the light leaving the slit onto the screen by
D sin θ = mλ
where D sin θ is the path length of the waves, each.
mλ is the wavelength of the wavelet
where m is the the order of each minimum
m = m = 1,−1,2,−2,3, . . .
The wavelength of each wavelet is always a multiple of the wavelength of the light source, and from the equation, we can see that the angle of diffraction depend on the wavelength of the light. From this we can see that increasing the wavelength of the light increases the angle of diffraction, and hence we can say that doubling the wavelength will double the diffraction angle. Also, the width of the central bright spot of the screen will spread or increase with the angle of diffraction, so doubling the wavelength doubles the central bright spot on the screen.
The answer is a,(what is the velocity of the current
Answer:
Explanation:
Given that,
A portable music player is operating with 4 cell batteries connected in series, and each cell has a P.D of 1.5V.
Then,
Total potential difference is
P.D_total = V1 + V2 + V3 + V4
P.D_total = 1.5 + 1.5 + 1.5 + 1.4
P.D_total = 6V.
The music player provides a resistance of 15,000Ω
R = 15,000Ω
We want to find the current (I) flowing through the music player?
Using ohms law
V = IR
Where
V is the potential difference
I is the current
R is the resistance
Therefore,
I = V/R
I = 6 / 15,000
I = 4 × 10^-4 A
I = 0.4 × 10^-3 A
I = 0.4 mA.
So, 0.4mA is passing through the music player
