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Zarrin [17]
2 years ago
6

Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34

Mathematics
1 answer:
exis [7]2 years ago
4 0

The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

Sin(θ)=3/4

We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

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The perimeter of a triangle is 30 units. If it is dilated with respect to origin by a scale factor of 0.5, what is the perimeter
il63 [147K]
<span>Choices: 30 units ; 20 units ; 15 units ;  7.5 units

Given:
perimeter = 30 units
scale factor = 0.5

30 units * 0.50 = 15 units

The perimeter of the resulting triangle is 15 units.</span>
6 0
3 years ago
What is the length of the the midsegment of a trapezoid with bases of length and ​?
Marina86 [1]

Answer:

The midsegment of a trapezoid is parallel to each base, and its length is one-half the sum of the lengths of the bases.

Step-by-step explanation:

3 0
2 years ago
The Rodriquez family is donating
laiz [17]

Subtract the blue caps:

25-11 = 14 caps are either white or green.

Let green = X

white = X +2

Green +  white = 14:

x + x +2 = 14

Combine like terms:

2x +2 = 14

Subtract 2 from both sides:

2x = 12

Divide both sides by 2:

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There are 11 blue caps, 6 green caps and 8 white caps.

5 0
3 years ago
Rectangle JKLM is rotated 90° clockwise about the origin.
shusha [124]

Answer:

Clockwise rotation 90 &deg; about origin

R_{90, clockwise, origin}(x,y) -> (y,-x)

J(-4,1) therefore

R_{90, clockwise, origin}J(-4,1) -> J'(1,+4)  this answer was form other person credits to him/her

Step-by-step explanation:

4 0
3 years ago
Simplify the expression.<br> -5+i/2i
Lostsunrise [7]

Answer:

\rm - \dfrac{11}{2}

Step-by-step explanation:

\rm Simplify \:  the  \: following: \\   \rm \longrightarrow - 5 +  \dfrac{i}{2} i \\  \\  \rm Combine \:  powers. \\  \rm  \dfrac{i \times i}{2}  =  \dfrac{i^{1 + 1}}{2}: \\  \rm \longrightarrow  - 5 +  \dfrac{i^{1 + 1}}{2}  \\  \\  \rm 1 + 1 = 2: \\ \rm \longrightarrow  - 5 +  \dfrac{i^2}{2}  \\  \\  \rm i^2 = -1: \\ \rm \longrightarrow  - 5 +   \dfrac{( - 1)}{2}   \\  \\  \rm \longrightarrow  - 5 -  \dfrac{1}{2}   \\  \\  \rm Put   \:   - 5 -  \dfrac{1}{2}   \: over  \: the  \: common \:  denominator  \: 2.  \\  \rm   - 5 -  \dfrac{1}{2}   =  \dfrac{2( -  5)}{2} -  \dfrac{1}{2}  : \\   \rm \longrightarrow  \dfrac{ - 5 \times 2}{2}  -  \dfrac{1}{2}  \\  \\  \rm 2 (-5) = -10: \\    \rm \longrightarrow    \dfrac{ - 10}{2}  -  \dfrac{1}{2}  \\  \\  \rm \dfrac{ - 10}{2}  -  \dfrac{1}{2}  =  \dfrac{ - 10 - 1}{2} : \\   \rm \longrightarrow \dfrac{ - 10 - 1}{2}  \\  \\  \rm -10 - 1 = -11: \\    \rm \longrightarrow  -  \dfrac{11}{2}

7 0
3 years ago
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