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Alex_Xolod [135]
3 years ago
6

If f(x) = 5x + 40, what is f(x) when x = -5? –9 -8 Ο Ο Ο Ο 7 15

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

The answer is 15.

Step-by-step explanation:

f(x) = 5x + 40

f(x)=5(-5)+40

f(x)=-25+40

f(x)=15

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Assume the exponential growth model ​A(t)equals=Upper A 0 e Superscript ktA0ekt and a world population of 5.95.9 billion in 2006
Whitepunk [10]

Answer:

1.4% is the maximum acceptable annual rate of​ growth such that the population must stay below 24 billion during the next 100​ years.

Step-by-step explanation:

We are given the following in the question:

The exponential growth model ​is given by:

A(t) = A_0e^{kt}

where k is the growth rate, t is time in years and A_0 is constant.

The world population is 5.9 billion in 2006.

Thus, t = 0 for 2006

A_0 = 5.9\text{ billions}

We have to find the maximum acceptable annual rate of​ growth such that the population must stay below 24 billion during the next 100​ years.

Putting these values in the growth model, we have,

24 = 5.9e^{100k}\\\\k = \dfrac{1}{100}\ln \bigg(\dfrac{24}{5.9}\bigg)\\\\k = 0.01403\\k = 0.01403\times 100\% = 1.4\%

1.4% is the maximum acceptable annual rate of​ growth such that the population must stay below 24 billion during the next 100​ years.

8 0
2 years ago
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
The temperature, T , of a given mass of gas varies inversely with its volume, V . The temperature of a certain gas with volume o
alekssr [168]
We know that

if t<span>he temperature T of a given mass of gas varies inversely with its volume V 
</span>then
T=k/V

Step 1
Find the value of k
for T=30º C and V=105 cm³
we have 
T=k/V--------> k=T*V--------> k=30*105=3150 °C*cm³

therefore
for V=84 cm³
T=3150/84=37.5 °C

the answer is 37.5 °C
3 0
3 years ago
At Appliance Market, a salesperson sells a dishwasher for $569. She gets a commission rate of 18 percent. Which expression repre
posledela
569/x=100/18
multiply both sides of the equation
569=5.55556
now we divide 
569/5.55556
102.42=x

18% of 569=102.42
4 0
3 years ago
Read 2 more answers
What would be 12.6 - 4.9 as an estimate?
-Dominant- [34]
I would say 8.0 Because if you do 12.6-4.9 you get 7.7 ...hope that helped
6 0
2 years ago
Read 2 more answers
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