Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence
Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be 
The next will be; 
The nth term will be 
For each of the successive terms to be less than the previous term;
then 
must be a proper fraction;
This implies that:
<em>Where 7 is the denominator</em>
<em>The sets of </em><em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>
Answer:
a = 8 ÷ 1/8
Step-by-step explanation:
All I really did was put another variable similar to the x in the original problem, then I changed the numbers to be a bit lower while still keep the original work-- In a short term, I lowered the 9s to 8s.
Answer:
you will have to get the graph :\
Step-by-step explanation:
sorry
58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6 - (1.21 * 2) = 72.6 - 2.42 = 70.18
