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3 years ago

Helpppp pleaseeeeeeee

Mathematics

1 answer:

Katena32 [7]3 years ago

3 0

The answer is B) multiply 3 by 3. With that 2 on top, that doesn't mean 3 times 2, that means multiply 3 by itself, however many times the number says, if that makes sense. So if there's a 2 above the 3, then that would be 3*3. If it was a 5 instead of a two, that would mean 3*3*3*3*3. Not 3*5.

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Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

4 0

3 years ago

Hello! please help with this question.

Harlamova29_29 [7]

Answer:

Step-by-step explanation:

A) more like parallel line

B) That is angle bisecting

C) Neither Angle or line bisector

3 0

3 years ago

5(-42/-7) + (-15) - (-3)

siniylev [52]

Answer:

2058

Step-by-step explanation:

8 0

3 years ago

Can someone answer this

Lunna [17]

Answer:

$m = \boxed{1} \: \: c = \boxed{4}$

Step-by-step explanation:

$y = x + 4 \\ equating \: it \: with \\ y = mx + c \\ m = \boxed{1} \: \: c = \boxed{4}$

8 0

3 years ago

Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?

frutty [35]

Answer:

Step-by-step explanation:

group them first :

( x3+5x2) and ( -6x-30)

then simply by gcf ( greatest common factor) :

x2(x+5) and -6(x+5)

and just add them together:

x2(x+5)-6(x+5)

bonus :

it can be written as (x2-6)(x+5)

6 0

3 years ago