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pishuonlain [190]

3 years ago

5

Which of the given functions could this graph represent? A. f(x) = x(x − 1)(x − 2)(x + 1)(x + 2) B. f(x) = x(x − 1)(x + 1) C. f(

x) = (x − 1)(x − 2)(x + 1)(x + 2) D. f(x) = x(x − 1)(x − 2)

2 answers:

zaharov [31]3 years ago

5 0

Answer:

The answer is B. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)

Step-by-step explanation:

maria [59]3 years ago

3 0

Answer:

B

Step-by-step explanation:

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Sally was walking to Ocean Front Housing Complex, In miles, how far is her distance?

Vanyuwa [196]

Answer:

Sally is 10 miles

The coordinate ofthe deli is (1, -1)

Step-by-step explanation:

✍️Coordinate of Sally = (-3, 2)

Coordinate of Ocean Front = (5, -4)

The distance of Sally to Ocean Front Housing Complex = the distance between point (-3, 2) and (5, -4).

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ , to calculate the distance between (-3, 2) and (5, -4):

$d = \sqrt{(5 -(-3))^2 + (-4 - 2)^2}$

$d = \sqrt{(8)^2 + (-6)^2}$

$d = \sqrt{64 + 36}$

$d = \sqrt{100} = 10$

✅The distance of Sally is 10 miles

✍️the coordinate of Deli would be half the distance between Sally and Ocean Front.

Therefore, use the midpoint formula to calculate the coordinate of the midpoint between Sally (-3, 2) and Ocean Front (5, -4).

Midpoint of (-3, 2) and (5, -4).

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Plug in the values

$M(\frac{-3 + 5}{2}, \frac{2 +(-4)}{2})$

$M(\frac{2}{2}, \frac{-2}{2})$

$M(1, -1)$

✅The coordinate ofthe deli is (1, -1)

8 0

2 years ago

When a graph of a cubic polynomial function rises to the left, it falls to the right true or false

serious [3.7K]

That would be true i think

6 0

3 years ago

Please help with this

11Alexandr11 [23.1K]

The answer is

4x^4-4x^3-16x^2+16x

4 0

3 years ago

Brandon earns $6 for every shirt he sell.which equation could Brandon use to determine the amount of money he earns for any numb

maw [93]

I got B. Hope it helps

8 0

3 years ago

crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

as

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

so

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

so

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

4 0

3 years ago