after losing 25 pounds an individual weighs 105 pounds more than one third of his previous weight. what is the previous weight ?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

5 0

X - 25 = 1/3x + 105
x - 1/3x = 105 + 25
2/3x = 130
x = 130 * 3/2
x = 390/2
x = 195 <==== previous weight

blagie [28]3 years ago

5 0

X-25 = 105 + 1/3(x)
-1/3(x) - 1/3(x)
2/3(x) - 25 = 105
+ 25 +25
2/3(x) = 130
*3/2 *3/2
x = 195
The individual’s weight before is about 195lb

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The question is incomplete! Complete question along with answers and step by step explanation is provided below.

Question:

(a) Binomial probability distributions depend on the number of trials n of a binomial experiment and the probability of success p on each trial. Under what conditions is it appropriate to use a normal approximation to the binomial? (Select all that apply.)

nq > 10

np > 5

p > 0.5

np > 10

p < 0.5

nq > 5

(b) What is the probability of "12" or fewer successes for a binomial experiment with 20 trials. The probability of success on a single trial is 0.50. Use the normal approximation of the binomial distribution to answer this question. (Round your answer to four decimal places.)

Answer:

(a) The correct options are np > 5 and nq > 5

(b) P(x ≤ 12) = 0.8133

Step-by-step explanation:

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