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2 years ago

Which of the following graphs correctly displays the data from the table

Mathematics

2 answers:

Leona [35]2 years ago

5 0

Answer:

graph A correctly display the data.

Step-by-step explanation:

Given : Table for class and frequency.

To find : Which of the following graphs correctly displays the data from the table.

Solution : We have given that

Table class : frequency

0.320 - 0.329 : 1

0.330 - 0.339 : 2

0.340 - 0.349 : 12

0.350 - 0.359 : 14

0.360 - 0.369 : 1

We can see from given table class 0.320 - 0.329 has 1 frequency and class 0.330 - 0.339 has 2 frequency .....so on.

From the graph A Show the same data.

Therefore, graph A correctly display the data.

blagie [28]2 years ago

4 0

A is the correct answer

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Ksivusya [100]

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3 years ago

Read 2 more answers

A long jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above an

slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is $y = -x^{2}+12\cdot x -27$ .

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Horizontal distance from the start line, measured in meters.

$y$ - Height of the long jumper, measured in meters.

$a$ , $b$ , $c$ - Polynomial constants, measured in $\frac{1}{m}$ , dimensionless and meters, respectively.

If we know that $(x_{1},y_{1}) = (3\,m, 0\,m)$ , $(x_{2},y_{2}) = (8\,m, 0.05\,m)$ and $(x_{3}, y_{3}) = (9\,m, 0\,m)$ , this system of linear equations is presented below:

$9\cdot a + 3\cdot b + c = 0$ (Eq. 1)

$81\cdot a + 9\cdot b + c = 0$ (Eq. 2)

$64\cdot a + 8\cdot b + c = 0.05$ (Eq. 3)

The coefficients of the polynomial are, respectively:

$a = -\frac{1}{100}$ , $b = \frac{3}{25}$ , $c = -\frac{27}{100}$

The equation of the parabola that models the path of the long jumper through the air is $y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}$ .