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hjlf
4 years ago
12

7. Which of the following equations is

Mathematics
1 answer:
Setler79 [48]4 years ago
3 0
It is B y = 2x + b so that is the answer
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at union middle school , 99 girls or 33% of the girl , play basketball.how many girls attend union middle school?
kolezko [41]

Answer:

300 girls

Step-by-step explanation:

100% represents the whole school

To calculate this amount divide 99 by 33% to find 1% and multiply by 100

school population = \frac{99}{33} × 100 = 3 × 100 = 300



5 0
3 years ago
Say that every single class in Full Sails Masters Degree in Game Design has a 5% failure rate per month. Say also that when a st
Leya [2.2K]
If there is a 5% drop every month, then the class becomes 1-5%=1-0.05=0.95 times the previous size.

The formula for t months would be
100*0.95^{t}
so for 12 months it would be
100*0.95^{12}\approx 54
6 0
3 years ago
Nickel-63 is a radioactive substance with a half-life of about 100 years. An artifact had
Marina CMI [18]

Answer:

see below

Step-by-step explanation:

The equation for half life is

n = no  e ^ (-kt)

Where no is the initial amount of a substance , k is the constant of decay and t is the time

no = 9.8

1/2 of that amount is 4.9 so n = 4.9 and t = 100 years

4.9 = 9.8 e^ (-k 100)

Divide each side by 9.8

1/2 = e ^ -100k

Take the natural log of each side

ln(1/2) = ln(e^(-100k))

ln(1/2) = -100k

Divide each side by -100

-ln(.5)/100 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/100 t)

Approximating ln(.5)/100 =-.006931472

n = 9.8 e^(-.006931472 t)  when t is in years

Now changing to days

100 years = 100*365 days/year

36500 days

Substituting this in for t

4.9 = 9.8 e^ (-k 36500)

Take the natural log of each side

ln(1/2) = ln(e^(-36500k))

ln(1/2) = -36500k

Divide each side by -100

-ln(.5)/36500 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/36500 d)

Approximating ln(.5)/365=-.00001899

n = 9.8 e^(-.00001899 d)  when d is in days

3 0
4 years ago
Read 2 more answers
On Friday night, the owner of Chez Pierre in downtown Chicago noted the amount spent for dinner for 28 four-person tables. 95 10
Shalnov [3]

Answer:

(a) The mean is 107.25, median is 106 and mode is 95.

(b) The data set is right-skewed.

Step-by-step explanation:

The sample space of amount spent for dinner for 28 four-person tables is:

S = {95, 103, 109, 170, 114, 113, 107, 124, 105, 80, 104, 84, 176, 115, 69, 95, 134, 108, 61, 160, 128, 68, 95, 61, 150, 52, 87, 136}

There are <em>n</em> = 28 values in the set.

(a)

The mean of this data set is:

\bar x=\frac{1}{n} \sum x=\frac{1}{28} \times3003=107.25

The mean is 107.25.

The data set consists of even number of observations.

The median for an even set of data is the mean of the middle two numbers.

First arrange the data set in ascending order:

52, 61 , 61 , 68 , 69 , 80 , 84 , 87 , 95 , 95 , 95 , 103 , 104 , 105 , 107 , 108 , 109 , 113 , 114 , 115 , 124 , 128 , 134 , 136 , 150 , 160 , 170 , 176

The median is the average value of the 14th and 15th observation.

Median=\frac{14^{th}obs.+15^{th}obs.}{2}=\frac{105+107}{2}=106

The median is 106.

The mode of a data set is the value with the most frequency.

Consider the arranged data set.

52, 61 , 61 , 68 , 69 , 80 , 84 , 87 , 95 , 95 , 95 , 103 , 104 , 105 , 107 , 108 , 109 , 113 , 114 , 115 , 124 , 128 , 134 , 136 , 150 , 160 , 170 , 176

The value 95 is repeated most of the times.

Thus, the mode is 95.

(b)

The value of mean, median and mode are related as follows:

Mean > Median > Mode

This implies that the data is skewed.

In case of a right-skewed data the Mean > Median > Mode.

In case of left skewed data the Mean < Median < Mode.

Thus, the data set is right-skewed.

8 0
3 years ago
An airplane flies 105 miles in 1/2 hour how far can it fly in 1 and 1/4 at the same rate of speed
Zigmanuir [339]

262.5 miles.

105 x 2 = 210

105 ÷ 2 = 52.2

210 + 52.2 = 262.5 miles

3 0
4 years ago
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