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2 years ago

15

the width of a rectangle is 7 meters greater than its length.If the area of the rectangle is 170 square meters, write the quadra

tic equation in standard form for the equation that would represent the area of the rectangle. Let x equal the length of the rectangle.

1 answer:

Anika [276]2 years ago

4 0

Answer:

$x^2+7x-170 = 0$

Step-by-step explanation:

To calculate an area of a rectangle, use the formula A=l*w. We know the width is 7m greater than the length. So w = 7 + x. So the area is A= (7+x)*x.

We also know the area is 170. Substitute this value for A and solve.

$170 = (7+x)(x)\\170 = 7x+x^2\\x^2+7x-170 = 0$

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The factors of $2(x+y)^2-9(x+y)-5$ is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=> $2(x+y)^2-9(x+y)-5$

To Find:

The factors of the polynomial =?

Solution:

Lets assume k = (x+y)

Then $2(x+y)^2-9(x+y)-5$ can be written as $2k^2-9k-5$

Now by using quadratic formula

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Substituting the values, we get

k = $\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}$

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Solving the RHS we get

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Substituting k = x+y

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