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timurjin [86]
3 years ago
7

Do participate Cora Alaskan owl Bruce​

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

you are supposed to ask a real question aren't you, I'm not sure if that is a question

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There are only 5 blue cards, 2 green cards and 4 red cards in a pack.
Ainat [17]

Answer:

5/11 or 45 percent, since there are 5 blue cards

3 0
3 years ago
Help? pls i mark brainlest answer
Delicious77 [7]

Answer:

3x-13 = 32 degrees

x= 15 degrees

Step-by-step explanation:

i dont think you need to show work so ill keep this short and simple :)

6 0
3 years ago
Read 2 more answers
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0
3 years ago
Read 2 more answers
A gate is made up of a rectangle and has a height of 6ft find the area of the gate
Snezhnost [94]

Answer: The area is 18ft

6 0
3 years ago
3ax-n/5=-4 solve for x
jasenka [17]
3ax-\frac{n}{5}=-4\ \ \ |Add\ \frac{n}{5}\ to\ both\ sides\\\\
3ax=-4+\frac{n}{5}\\\\
3ax=-\frac{20}{5}+\frac{n}{5}\\\\
3ax=\frac{-20+n}{5}\ \ \ |Divide\ by\ 3a\\\\
x=\frac{-20+n}{5}*\frac{1}{3a}\\\\
x=\frac{-20+n}{15a}\\\\Asnwer\ is\ x=\frac{-20+n}{15a}.
5 0
3 years ago
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