Answer:
Given
Edge of a cube = 10cm
Length, l = 12.5 cm
Breadth, b = 10cm
Height, h = 8 cm
Find out
We have to find
i) Which box has the greater lateral surface area and by how much?
ii) Which box has the smaller total surface area and by how much?
Solution
(i)
Lateral surface area of a cube = 4 * (edge)2
= 4 * 102 cm2
= 400 cm2
Lateral surface area of a cuboid = 2 (lh + bh)
= 2 (12.5 * 8 + 10 * 8) cm2
= 2 (100 + 80) cm2
= 360 cm2
So, the lateral surface area of the cubical box is greater than cuboidal box by (400 cm2 – 360 cm2) which is 40 cm2.
(ii)
Total surface area of a cube = 6 * (edge)2
= 6 * 102 cm2
= 600 cm2
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (12.5 * 10 + 10 * 8 + 12.5 * 8) cm2
= 2 (125 + 80 + 100) cm2
= 610 cm2
Therefore, the total surface area of the cuboidal box is greater than the cubical box by (610 cm2 – 600 cm2) which is 10 cm2.
Answer:
A.) The red cylinder.
Step-by-step explanation:
For a cylinder:
V = (1/3)(pi)r^2h
Red:
V = (1/3)(pi)(2^2)(4) = 16pi/3
Blue:
V = (1/3)(pi)(1^1)(8) = 8pi/3
Since 16pi/3 is greater than 8pi/3, the red cylinder has a greater volume.
Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Answer: No
Step-by-step explanation:
The diver is at 60m below sea level, and swims upward 2m every 5 seconds.
So, since there are 24 five-second periods in 2 minutes (60secs/min), the diver would have swam up 48m after 2 minutes.
Since 60m - 48m is 12m, the diver has not yet reached the sea surface.
Hope it helps :)
It is .21 or 21 cents for each pound.
