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Ivan
3 years ago
10

What is the greatest common factor of 12t3+30t2+48t

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

6t

Step-by-step explanation:

The greatest common of 12t^3, 30t^2, and 48t:

First, we see that t divides into every term. We also see that the greatest common factor of the coefficients 12, 30, and 48 is 6. So the greatest common factor of the three terms is 6t.

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Since, the length of each piece is 2/9 foot, the length of 27 pieces would be:

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This means, Arsenio needs 6 feet in total for the copper tubing. Since he got 8 feet in total, he has sufficient amount of tubing available.

After making the 27 pieces, he will be left with 8 - 6 = 2 feet of tubing.

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