What is the greatest common factor of 12t3+30t2+48t
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Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams