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3 years ago

I need all the answers I suck at this

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

1) 0.7
2) 0.627
3) 0.371
4)0.130
5) 0.66
6) 0.36
7)0.38
8)0.15

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The sum of 8 and x is less than 23?

Charra [1.4K]

Answer: no not less than 23

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3 years ago

PLEASE HELP!!!! I HAVE TO SUBMIT THIS IN AND I DONT KNOW!!

masya89 [10]

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Step-by-step explanation:

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3 years ago

Determine the intercepts of the line.<br> y-6= 4( + 5)<br> y-intercept:<br> z-intercept

Shtirlitz [24]

Answer:

(0, 26)
(-6.5, 0)

Step-by-step explanation:

Turn the equation into slope-intercept form [ y = mx + b ].

y - 6 = 4(x + 5)

y - 6 = 4x + 20

y = 4x + 26

We know that b = y-intercept for the y-intercept is 26.

Substitute 0 for y to find the x intercept.

0 = 4x + 26

-26 = 4x

-6.5 = x

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3 years ago

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monitta

Answer:=15x^2+250x

Step-by-step explanation:

8 0

2 years ago

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Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

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3 years ago

Read 2 more answers