What is the length of the radius of a circle with a center at 2 – i and a point on the circle at 8 + 7i? 8 10?

Mathematics

2 answers:

Leni [432]3 years ago

7 0

Using the distance formula:-

radius = √ ( (8 - 2)^2 + (7 - -1)^2 )

= √ (6^2 + 8^2) = √100 = 10 (answer)

Sidana [21]3 years ago

7 0

Answer:

The answer is C, 10!

You might be interested in

Which is the range of the discrete function G(x)?

Shkiper50 [21]

The range of the discrete function is C- 2,5,9

8 0

3 years ago

Alexander and Jo live 5 miles apart. They decide to leave their homes at 3 p.M. And travel toward each other. If Alexander bikes

lukranit [14]

Answer:

Step-by-step explanation:

Here is an illustration of the problem:

----------------------------->|<------------------

A t J

Alex and Jo start from their separate homes and drive towards one another. The t indicates the time at which they meet, which is the same time for both. Filling in a d = rt table:

d = r x t

Alex 14 t

Jo 6 t

The formula for motion is d = rt, so that means that Alex's distance is 14t and Jo's distance is 6t.

14t 6t

---------------------------------->|<------------------

A t J

The distance between them is 5 miles, so that means that Alex's distance plus Jo's distance equals 5 miles. In equation form:

14t + 6t = 5 and

20t = 5 so

t = .25 hours or 15 minutes.

If they leave their homes at 3 and they meet 15 minutes later, then they meet at 3:15.

3 0

3 years ago

A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk

Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = $1 *10^6$ bytes

kilobyte = $1*10^3$ bytes

and a regular byte would just be $1$

Now, you will need to do a conversion:

$1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}$

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are $1*10^6$ bytes!)

In the second fraction thought, remember one kilobyte is $1*10^3$ bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do $\frac{1kilobyte}{1*10^3bytes}$ , but I think it is more correct to do write it out how I did).