All categories

2 years ago

Let W be a point between points U and V on

1 answer:

4 0

So if point W is somewhere on the line segment UV, then the equation UV = UW + WV is true.

$UV = UW + WV\\(13)=(2y-9)+(y-5)\\13=2y-9+y-5\\13=(2y+y)+[(-9)+(-5)]\\13=3y-14\\27=3y\\\\y=9$

You might be interested in

What’s the rate of -5x - 6

Art [367]

Answer:

Step-by-step explanation:

7 0

2 years ago

Gerry wants to construct a triangle with segments that

alexira [117]

Answer:

See Explanation

Step-by-step explanation:

Sample Response: No, the triangle is not possible. The triangle inequality rule states the sum of any two sides must be greater than the third side. 6 + 4 is 10, which is less than 11.

5 0

2 years ago

Kavi solved the system

Marianna [84]

Answer:

She should have substituted y = 17 - 2x in the first equation

Step-by-step explanation:

3x + 4y = 33

2x + y = 17

y = 17 - 2x

3x + 4(17 - 2x) = 33

3x + 68 - 8x = 33

5x = 35

x = 7

y = 17 - 2(7)

y = 3

x = 7, y = 3

Only one solution

6 0

3 years ago

Do not understand please help Thank u

AysviL [449]

Answer:

43.4

Step-by-step explanation:

You will need to use the phythagoream therom, which is a² + b² = c². Plug the values in for the variables to get 7² + b² = 44², (c would equal the hypothenuse because the hypothenuse is the longest side of the triangle.) Square the values to get 49 + b² = 1936. Subtract 49 from both sides to get b² = 1887, then take the square root of both sides to get b = 43.4 (rounded to the nearest tenth.)

I am really sorry if I'm wrong, but have a good day/night! :)

6 0

2 years ago

Read 2 more answers

A study found that a 95% confidence interval for the mean μ of a particular population was computed from a random sample of 1200

kotykmax [81]

Answer:

95% confidence interval for the mean μ is (6,14)

The Population mean μ lies between ( 6, 14 )

Step-by-step explanation:

Explanation:-

Given random sample 'n' = 1200

95% confidence interval for the mean μ is determined by

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$

Level of significance = 95% 0r 0.05

Z₀.₀₅ = 1.96

$(x^{-} -Z_{\alpha } \frac{S.D}{\sqrt{n} } , x^{-} +Z_{\alpha } \frac{S.D}{\sqrt{n} } )$ = 10 ± 4

Mean of the small sample = 10

95% of confidence intervals are

( 10 ±4 )

( 10 -4 , 10+4)

( 6 , 14 )

95% confidence interval for the mean μ lies between ( 6, 14 )

8 0

2 years ago