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2 years ago

Let W be a point between points U and V on

1 answer:

4 0

So if point W is somewhere on the line segment UV, then the equation UV = UW + WV is true.

$UV = UW + WV\\(13)=(2y-9)+(y-5)\\13=2y-9+y-5\\13=(2y+y)+[(-9)+(-5)]\\13=3y-14\\27=3y\\\\y=9$

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What is greater -5.06 or 5.6

sukhopar [10]

$-5.06 < 5.6 \\\\ 5.6 -is \ a \ positive \ number \ so \ is \ always \ bigger \ than \ a \ negative \ one$

4 0

2 years ago

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6. Which TWO sets of numbers

Ostrovityanka [42]

Answer:

A and D

Step-by-step explanation:

A: 12-7=5

B: 13-6=7

C: 11-8=3

D 14-9=5

Have a Fantastic Day! :D

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2 years ago

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Please answer these thank u

balu736 [363]

1. 3*3 + 3*8 = 9+24=33

2. 4*4+.5*2*4+5*5= 16+4+25=45

3. 5*10+4*10= 90

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2 years ago

The area of the right triangle shown is 24 square feet.

Goryan [66]

The equations used to find the length of leg of triangle are:

$0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100$

Solution:

From given,

Area of right triangle = 24 square feet

Also from given figure in question (attached below )

base = x and height = x + 2

The area of triangle is given by formula:

$Area = \frac{1}{2} \times base \times height$

Substituting the values we get,

$24 = \frac{1}{2} \times x \times (x+2)\\\\24 = 0.5x(x + 2)\\\\48 = x(x+2)\\\\x^2 + 2x - 48 = 0\\\\$

Also, the above equation can be written as,

$x^2 + (x+2)^2 =100$

Thus the equations used to find the length of leg of triangle are:

$0.5x(x+2) = 24\\\\x^2+2x-48=0\\\\x^2+(x+2)^2 = 100$

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2 years ago

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Find the area of the parallelogram please.

Deffense [45]

13·19·SIN(60°) = 213.9

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2 years ago