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Alex17521 [72]
4 years ago
12

What is the factored form of 6n4 – 24n3 + 18n?

Mathematics
2 answers:
enot [183]4 years ago
8 0
6n^4-24n^3+18n
6n(n^3-4n^2+3)
6n(n-1)(n^2-3n-3)

Rama09 [41]4 years ago
4 0

Answer:

Step-by-step explanation:

Notice to facts:

  • The numbers 6, -4 and 18 have a common factor: 6.
  • In all the terms (n⁴, n³, n) are a factor n.

The expression has a common factor 6n. Then,

6n⁴-24n³+18n = 6n(n³-4n²+3).

In order to factor the term n³-4n²+3 we use Ruffini-Horner rule, which gives us that

n³-4n²+3 = (n-1)(n²-3n-3).

Then,

6n⁴-24n³+18n = 6n(n³-4n²+3) = 6n(n-1)(n²-3n-3).

If you don't know the formula for the general solution of second degree equation, you are done. Otherwise, it is only to use it in the quadratic factor.

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